problem 788. Rotated Digits solution1: class Solution { public: int rotatedDigits(int N) { ; ; i<=N; ++i) { if(check(i)) res++; } return res; } bool check(int num) { string str = to_string(num); bool flag = false; for(auto ch:str) { ') return false;…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/rotated-digits/description/ 题目描述 X is a good number if after rotating each digit individually by 180 degrees, we get a valid number that i…

题目如下: An integer has sequential digits if and only if each digit in the number is one more than the previous digit. Return a sorted list of all the integers in the range [low, high] inclusive that have sequential digits. Example 1: Input: low = 100,…

problem 949. Largest Time for Given Digits solution: class Solution { public: string largestTimeFromDigits(vector<int>& A) { sort(A.begin(), A.end(), greater<int>());//errr..largest.. do { ]< || (A[]==&&A[]<)) && A[]&…

题目要求 X is a good number if after rotating each digit individually by 180 degrees, we get a valid number that is different from X.  Each digit must be rotated - we cannot choose to leave it alone. A number is valid if each digit remains a digit after…

Add Digits Given a non-negative integer num, repeatedly add all its digits until the result has only one digit. For example: Given num = 38, the process is like: 3 + 8 = 11, 1 + 1 = 2. Since 2 has only one digit, return it. Follow up:Could you do it…

题目: Given a non-negative integer num, repeatedly add all its digits until the result has only one digit. For example: Given num = 38, the process is like: 3 + 8 = 11, 1 + 1 = 2. Since 2 has only one digit, return it. Follow up:Could you do it without…

X is a good number if after rotating each digit individually by 180 degrees, we get a valid number that is different from X.  Each digit must be rotated - we cannot choose to leave it alone. A number is valid if each digit remains a digit after rotat…

https://leetcode.com/problems/rotated-digits/ X is a good number if after rotating each digit individually by 180 degrees, we get a valid number that is different from X.  Each digit must be rotated - we cannot choose to leave it alone. A number is v…

X is a good number if after rotating each digit individually by 180 degrees, we get a valid number that is different from X.  Each digit must be rotated - we cannot choose to leave it alone. A number is valid if each digit remains a digit after rotat…