New Year is coming in Tree World! In this world, as the name implies, there are n cities connected by n - 1 roads, and for any two distinct cities there always exists a path between them. The cities are numbered by integers from 1 to n, and the roads…

D. New Year Santa Network   New Year is coming in Tree World! In this world, as the name implies, there are n cities connected by n - 1 roads, and for any two distinct cities there always exists a path between them. The cities are numbered by integer…

D. New Year Santa Network time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output New Year is coming in Tree World! In this world, as the name implies, there are n cities connected by n - 1 roads,…

题目大意 给你一颗有\(n\)个点的树\(T\),边上有边权. 规定,\(d(i,j)\)表示点i到点j路径上的边权之和. 给你\(q\)次询问,每次询问格式为\(i, j\),表示将按输入顺序排序的第\(i\)条边边权修改为\(j\),并要求回答任取三个不同点\(c_1,c_2,c_3\),所带来的费用\(d(c_1,c_2)+d(c_1,c_3) + d(c_2,c_3)\)的期望 原题面 D. New Year Santa Network time limit per test 2 sec…

D. New Year Santa Network time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output New Year is coming in Tree World! In this world, as the name implies, there are n cities connected by n - 1 roads,…

Codeforce 500 D. New Year Santa Network 解析(思維.DFS.組合.樹狀DP) 今天我們來看看CF500D 題目連結 題目 給你一棵有邊權的樹,求現在隨機取\(3\)點,求這三點互相距離總和的期望值. 前言 今天寫的題目都是看解答就會寫,原本就沒有的自信心又要更低了 @copyright petjelinux 版權所有 觀看更多正版原始文章請至petjelinux的blog 想法 \(3\)個點要考慮的事情太多了,首先只要注意到以下一件事,那麼其他的事情就和…

解题思路 \(dsu\) \(on\) \(tree\)的模板题.暴力而优雅的算法,轻儿子的信息暴力清空,重儿子的信息保留,时间复杂度\(O(nlogn)\) 代码 #include<iostream> #include<cstdio> #include<cstring> #include<cstdlib> #include<algorithm> #include<set> using namespace std; const int…

[题目链接]:http://codeforces.com/problemset/problem/500/D [题意] 有n个节点构成一棵树; 让你随机地选取3个不同的点a,b,c; 然后计算dis(a,b)+dis(b,c)+dis(a,c)的期望; 不止如此; 这里边还会减小; 要求你动态维护这个期望 [题解] 我们在选取这3个点的时候; 从最后的结果出发; 先取其中两个点(a,b); 则第三个点必然是从剩余的n-2个点中取出的; 也就是说有n-2条(a,b)路径最后需要算进答案; 而对于任选…

直接按边分,2个点在边的一边,1个在另一边,组合出来就是这个边对答案的贡献,权值换了就再重新算个数而已. #include <bits/stdc++.h> #define LL long long using namespace std; inline int ra() { ,f=; char ch=getchar(); ; ch=getchar();} +ch-'; ch=getchar();} return x*f; } LL n,m,cnt=; double ans,tot; struc…

Andrewid the Android is a galaxy-known detective. Now he is preparing a defense against a possible attack by hackers on a major computer network. In this network are n vertices, some pairs of vertices are connected by m undirected channels. It is pla…