HDU-5532 Almost Sorted Array (LIS)】的更多相关文章

Problem Description We are all familiar with sorting algorithms: quick sort, merge sort, heap sort, insertion sort, selection sort, bubble sort, etc. But sometimes it is an overkill to use these algorithms for an almost sorted array. We say an array…
We are all familiar with sorting algorithms: quick sort, merge sort, heap sort, insertion sort, selection sort, bubble sort, etc. But sometimes it is an overkill to use these algorithms for an almost sorted array. We say an array is sorted if its ele…
题目链接 Problem Description We are all familiar with sorting algorithms: quick sort, merge sort, heap sort, insertion sort, selection sort, bubble sort, etc. But sometimes it is an overkill to use these algorithms for an almost sorted array. We say an a…
题目大意:给一个n个数的序列,问这个序列删掉一个数后是否有序. 题目分析:找最长上升子序列和最长下降子序列,只要有一个的长度不小于n-1即可. 代码如下: # include<iostream> # include<cstdio> # include<cmath> # include<vector> # include<list> # include<queue> # include<map> # include<s…
描述 Follow up for ”Search in Rotated Sorted Array”: What if duplicates are allowed?    Would this affect the run-time complexity? How and why?    Write a function to determine if a given target is in the array. 如果循环数组里有重复元素,则根据A[m]>=A[l]是无法判断出(m,l)之间是…
Almost Sorted Array Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 236    Accepted Submission(s): 113 Problem Description We are all familiar with sorting algorithms: quick sort, merge sort,…
Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this in place with constant memory. For example,Given input array A = […
Almost Sorted Array Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 2504    Accepted Submission(s): 616 Problem Description We are all familiar with sorting algorithms: quick sort, merge sort,…
[问题描写叙述] Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array. Note: You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2. The number of elem…
想了一下感觉和lis有关,交了果然AC.想不到很好的证明方法,试做证明如下:lis的每一个点都是一个不上升系统中的一员,设其为a[i],那么a[i-1]<a[i]肯定是成立的(lis的性质),夹在这两者之间的一个元素x,如果其>=a[i],那么它肯定属于a[i]这个系统,如果它小于a[i],且:1.大于a[i-1]的话,违背了lis的性质,2.<=a[i-1]的话,x属于a[i-1]这个系统.不可能有别的情况了. 归纳如下:给定一个序列,它的LIS长度就是它非上升子序列的个数. 代码如下…