hdu1394--Minimum Inversion Number（线段树求逆序数，纯为练习）

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[HDU] 1394 Minimum Inversion Number [线段树求逆序数]

Minimum Inversion Number Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 11788 Accepted Submission(s): 7235 Problem Description The inversion number of a given number sequence a1, a2, ..., an…

HDU_1394_Minimum Inversion Number_线段树求逆序数

Minimum Inversion Number Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 16686 Accepted Submission(s): 10145 Problem Description The inversion number of a given number sequence a1, a2, ..., a…

hdu1394(Minimum Inversion Number)线段树

明知道是线段树,却写不出来,搞了半天,戳,没办法,最后还是得去看题解(有待于提高啊啊),想做道题还是难啊. 还是先贴题吧 HDU-1394 Minimum Inversion Number Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 8324 Accepted Submission(s): 5115 Problem Descri…

HDU-1394 Minimum Inversion Number 线段树+逆序对

仍旧在练习线段树中..这道题一开始没有完全理解搞了一上午,感到了自己的shabi.. Minimum Inversion Number Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 15527 Accepted Submission(s): 9471 Problem Description The inversion number of a…

HDU.1394 Minimum Inversion Number (线段树单点更新区间求和逆序对)

HDU.1394 Minimum Inversion Number (线段树单点更新区间求和逆序对) 题意分析给出n个数的序列,a1,a2,a3--an,ai∈[0,n-1],求环序列中逆序对最少的个数. 前置技能环序列还线段树的逆序对求法逆序对:ai > aj 且 i < j ,换句话说数字大的反而排到前面(相对后面的小数字而言) 环序列:把第一个放到最后一个数后面,就是一次成环,一个含有n个元素序列有n个环序列. 线段树的逆序对求法:每个叶子节点保存的是当前值数字的个数.根…

hdu 13394 Minimum Inversion Number 线段树

题意: 首先给你一个长度为n的序列v,你需要首先找出来逆序对(i<j && v[i]>v[j]) 然后把这个序列的最后一个元素放在第一个位置上,其他元素都向后移动一位. 一直这样操作,会得到n个序列,问你这n个序列中,哪个序列中的逆序对数最少,并输出题解: 首先我们可以通过线段树得到最初哪个序列的逆序对数,其实也可以通过归并排序得到,因为我是练习线段树,所以用的线段树写的线段树求逆序对数的话,我们可以求出来v[i]可以和v[j]形成的逆序对数,这个j的取值范围为1<=…

HDU-1394 Minimum Inversion Number（线段树求逆序数）

Minimum Inversion Number Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 15675 Accepted Submission(s): 9569 Problem Description The inversion number of a given number sequence a1, a2, -, an is the…