传送门:https://codeforces.com/gym/100801 题意: 小明坐地铁,现在有n-1种类型的地铁卡卖,现在小明需要买一种地铁票,使得他可以在t的时间内到达终点站,地铁票的属性为r,表明这个地铁票一次最多只能做r站,可以坐到当前位置的pos-r到pos+r范围的任意一站,到站后他需要花费di的时间重新上地铁. 现在问你最小的花费是多少. 题解: 已知我们可以在pos-r到pos+r内的范围的任意一站的位置下车,那么如果我范围为r的票可以在规定时间内到达终点站的话,我的r+1…

Problem J. Journey with Pigshttp://codeforces.com/gym/241680/problem/J考察排序不等式算出来单位重量在每个村庄的收益,然后生序排列猪的重量也生序排列此时价值最大 #include<iostream> #include<cstdio> #include<queue> #include<algorithm> #include<cmath> #include<ctime>…

传送门:https://codeforces.com/gym/100801 题意: 给你一个DAG图,你最多可以进行k次操作,每次操作可以连一条有向边,问你经过连边操作后最小拓扑序的最大值是多少 题解: 最小拓扑序:与普通拓扑序不同的是,用一个小根堆记录入度为0的点做拓扑排序即可 怎么样使得最小拓扑序最大呢?已知拓扑序是入度小的点在前面,那么,如果我们可以使得大的点的度数尽量小或者是小的点度数尽量大就可以使得拓扑序变大了,由于我们只有加边的操作,那么我们可以将边尽量从大的点往小的点去连边 我们定…

Problem J. Triatrip Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/gym/100342/attachments Description The travel agency “Four Russians” is offering the new service for their clients. Unlike other agencies that only suggest one-way…

Problem J. TriatripTime Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/gym/100342/attachments Description The travel agency “Four Russians” is offering the new service for their clients. Unlike other agencies that only suggest one-way…

J. Deck Shuffling Time Limit: 2   Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/gym/100187/problem/J Description The world famous scientist Innokentiy continues his innovative experiments with decks of cards. Now he has a deck of n cards and k…

Problem J. Bye Bye RussiaTime Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/gym/100500/attachments Description It was the last day at Russia, after the World Finals has ended. Coach fegla was travelling back to Cairo on the same day b…

Problem J. Joke 题目连接: http://codeforces.com/gym/100714 Description The problem is to cut the largest possible number of circles with diameter y out of a stripe of length x and width y. Input The only line of input consists of two positive real number…

#define null ""是用来将字符串清空的 #define none -1是用来当不存在这种动物时,返回-1. 其实这种做法有点多余,不过好理解一些. Home Web Board ProblemSet Standing Status Statistics   Problem J: 动物爱好者 Problem J: 动物爱好者 Time Limit: 1 Sec  Memory Limit: 128 MBSubmit: 509  Solved: 376[Submit][Stat…

Problem J Joking with Fermat's Last Theorem Fermat's Last Theorem: no three positive integers a, b, and c can satisfy the equation an + bn = cn for any integer value of n greater than two. From the theorem, we know that a3 + b3 = c3 has no positive i…