题目:我们会传递给你一个包含两个数字的数组.返回这两个数字和它们之间所有数字的和. 最小的数字并非总在最前面. /*方法一: 公式法 (首+末)*项数/2 */ /*两个数比较大小的函数*/ function compare(value1,value2){ if(value1 < value2){ return -1; }else if(value1 > value2){ return 1; }else{ return 0; } } function sumAll(arr) { arr.sor…

Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 m…

Given a Binary Search Tree and a target number, return true if there exist two elements in the BST such that their sum is equal to the given target. Example 1: Input: 5 / \ 3 6 / \ \ 2 4 7 Target = 9 Output: TrueExample 2: Input: 5 / \ 3 6 / \ \ 2 4…

Design and implement a TwoSum class. It should support the following operations: add and find. add - Add the number to an internal data structure.find - Find if there exists any pair of numbers which sum is equal to the value. For example, add(1); ad…

Given a Binary Search Tree and a target number, return true if there exist two elements in the BST such that their sum is equal to the given target. Example 1: Input: 5 / \ 3 6 / \ \ 2 4 7 Target = 9 Output: True Example 2: Input: 5 / \ 3 6 / \ \ 2 4…

1. 原始题目 给定一个已按照升序排列 的有序数组,找到两个数使得它们相加之和等于目标数. 函数应该返回这两个下标值 index1 和 index2,其中 index1 必须小于 index2. 说明: 返回的下标值(index1 和 index2)不是从零开始的. 你可以假设每个输入只对应唯一的答案,而且你不可以重复使用相同的元素. 示例: 输入: numbers = [2, 7, 11, 15], target = 9 输出: [1,2] 解释: 2 与 7 之和等于目标数 9 .因此 in…

Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number.The function twoSum should return indices of the two numbers such that they add up to the target, where index1 mu…

给定一个已按照升序排列 的有序数组,找到两个数使得它们相加之和等于目标数.函数应该返回这两个下标值 index1 和 index2,其中 index1 必须小于 index2.请注意,返回的下标值(index1 和 index2)不是从零开始的.你可以假设每个输入都只有一个解决方案,而且你不会重复使用相同的元素.输入:数组 = {2, 7, 11, 15}, 目标数 = 9输出:index1 = 1, index2 = 2详见:https://leetcode.com/problems/two-…

我们会传递给你一个包含两个数字的数组.返回这两个数字和它们之间所有数字的和. 最小的数字并非总在最前面. 这是一些对你有帮助的资源: Math.max() Math.min() Array.reduce() 感觉这些有用的资源对我来说没什么用..不就是等差数列求和么,于是 function sumAll(arr) { var nArr=arr.sort(function(x,d){ return x-d; }); return (nArr[0]+nArr[1])*(nArr[1]-nArr[0]…

You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.You may assume the two numbers…