uva 465 - Overflow  Overflow  Write a program that reads an expression consisting of two non-negative integer and an operator. Determine if either integer or the result of the expression is too large to be represented as a ``normal'' signed integer (…

上次那个大数开方的高精度的题,UVa113 Power of Cryptography,直接两个double变量,然后pow(x, 1 / n)就A过去了. 怎么感觉UVa上高精度的题测试数据不给力啊... 话说回来,我写了100+行代码,WA了,后来考虑到要忽略前导0,又WA了,实在不知道哪出问题了.  Overflow  Write a program that reads an expression consisting of twonon-negative integer and an…

 Overflow  Write a program that reads an expression consisting of twonon-negative integer and an operator. Determine if either integer orthe result of the expression is too large to be represented as a``normal'' signed integer (typeinteger if you are…

题目 Volume 0. Getting Started 开始10055 - Hashmat the Brave Warrior 10071 - Back to High School Physics 10300 - Ecological Premium 458 - The Decoder 494 - Kindergarten Counting Game 414 - Machined Surfaces 490 - Rotating Sentences 445 - Marvelous Mazes…

如用到bign类参见大整数加减乘除模板 424 - Integer Inquiry #include <iostream> #include <string> #include <cstring> #include <cstdio> #include <cstdlib> #define N 10050 using namespace std; string s; int ans[N]; int main() { int i, j; ] != ')…

这里的高精度都是要去掉前导0的, 第一题:424 - Integer Inquiry UVA:http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=97&page=show_problem&problem=365 解题思路:模拟手动加法的运算过程,写一个高精度整数加法就可以了:减法,乘法,除法同样也是模拟手动过程. 解题代码: #include <iostream&g…

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白书一:http://acm.hust.edu.cn/vjudge/contest/view.action?cid=64609#overview 注意UVA没有PE之类的,如果PE了显示WA. UVA401:Palindromes #include <iostream> #include <cstdio> #include <cstring> #include <cstdlib> #include <algorithm> using namesp…

http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=465&page=show_problem&problem=2399 最长的很简单,将串翻转过来后求两个串的lcs就是答案.. 主要是字典序那里... 还是开string来比较吧.. 注意最后输出方案时用前半段推出后半段.(因为可能lcs时会重合...) #include <cstdio> #include…

转载请注明: 仰望高端玩家的小清新 http://www.cnblogs.com/luruiyuan/ 题目大意: 题目传送门:UVa 10562Undraw the Trees 给定字符拼成的树,将这些树转换成特定的括号表示的树 思路: 首先,观察样例,可以发现就是先序遍历的顺序,因此可以确定dfs 但是,还有几个地方需要考虑: 同一级的结点,在同一级的括号中 由于顺序满足先序遍历,因此不需要存储树的括号表示法,更不需要构建树,直接在遍历过程中输出即可. 空树:即输入为:# 时的树的处理,我不…