题目如下: Given an array nums of integers, a move consists of choosing any element and decreasing it by 1. An array A is a zigzag array if either: Every even-indexed element is greater than adjacent elements, ie. A[0] > A[1] < A[2] > A[3] < A[4] &…

Difficulty:easy  More:[目录]LeetCode Java实现 Description Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbe…

今天看到LeetCode OJ题目下方多了"Show Tags"功能.我觉着挺好,方便刚開始学习的人分类练习.同一时候也是解题时的思路提示. [题目] Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). Find the minimum element. You may assume no…

作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 遍历 二分查找 日期 题目地址:https://leetcode-cn.com/problems/search-in-a-sorted-array-of-unknown-size/ 题目描述 Given an integer array sorted in ascending order, write a function to search targ…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 方法一:模拟过程 方法二:求和-n*最小值 方法三:排序 日期 [LeetCode] 题目地址:https://leetcode.com/problems/minimum-moves-to-equal-array-elements/ Difficulty: Easy 题目描述 Given a non-empty integer array of si…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 方法一:排序 方法二:直接找中位数 日期 题目地址:https://leetcode.com/problems/minimum-moves-to-equal-array-elements-ii/description/ 题目描述 Given a non-empty integer array, find the minimum number of m…

Given a non-empty integer array, find the minimum number of moves required to make all array elements equal, where a move is incrementing a selected element by 1 or decrementing a selected element by 1. You may assume the array's length is at most 10…

problem 453. Minimum Moves to Equal Array Elements 相当于把不等于最小值的数字都减到最小值所需要次数的累加和. solution1: class Solution { public: int minMoves(vector<int>& nums) { ;//err-initialization. int mn = INT_MAX;//err. for(auto num:nums) mn = min(num, mn); for(auto…

题目如下: Given a binary tree with the following rules: root.val == 0 If treeNode.val == x and treeNode.left != null, then treeNode.left.val == 2 * x + 1 If treeNode.val == x and treeNode.right != null, then treeNode.right.val == 2 * x + 2 Now the binary…

题目概述: Suppose a sorted array is rotated at some pivot unknown to you beforehand.(i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2).Find the minimum element.You may assume no duplicate exists in the array. 解题思路: 在一个有顺序的数组中查找个最小值,很容易想到的就是二分法,的确,这里用的就是二分,…