A string S of lowercase letters is given. We want to partition this string into as many parts as possible so that each letter appears in at most one part, and return a list of integers representing the size of these parts. Example 1: Input: S = "abab…
A string S of lowercase letters is given. We want to partition this string into as many parts as possible so that each letter appears in at most one part, and return a list of integers representing the size of these parts. Example 1: Input: S = "abab…
思路:动态规划.对于属于coins的coin,只要知道amount-coin至少需要多少个货币就能表示,那么amount需要的货币数目=amount-coin需要的货币数目+1:如果amount-coin都不能被表示,amount也不能被表示. 方法一:递归,由上至下. class Solution { Map<Integer, Integer> hashMap = new HashMap<>(); public int coinChange(int[] coins, int am…
A string S of lowercase letters is given. We want to partition this string into as many parts as possible so that each letter appears in at most one part, and return a list of integers representing the size of these parts. Example 1: Input: S = "abab…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 解题方法 日期 题目地址:https://leetcode.com/problems/partition-labels/description/ 题目描述 A string S of lowercase letters is given. We want to partition this string into as many parts as possible so…
[抄题]: A string S of lowercase letters is given. We want to partition this string into as many parts as possible so that each letter appears in at most one part, and return a list of integers representing the size of these parts. Example 1: Input: S =…
我一开始看数据范围很小,没怎么想就直接暴力了. 暴力的思路是: 对于每一段S的前缀,这个前缀中的每一个字母都不应该在前缀的补集中出现,所以直接循环i:0 to S.length然后对于每一次循环,再循环前缀中的每一个字母,判断是否在后面出现,如果出现就 说明该前缀不合适继续向后循环,如果没有出现就加入到vector里,并且下一次判断前缀时直接从sum(vector) 开始,所以时间复杂度应该是小于 n2 的. class Solution { public: vector<int> parti…
LeetCode: Palindrome Partition Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s. For example, given s = "aab", Return [ ["aa","b"], [&q…
Given an array A, partition it into two (contiguous) subarrays left and right so that: Every element in left is less than or equal to every element in right. left and right are non-empty. left has the smallest possible size. Return the length of left…
Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), ..., (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible. Example 1: Input: [1,4,3,2] Output: 4 Explan…