654. Maximum Binary Tree 题目大意: 意思就是给你一组数,先选一个最大的作为根,这个数左边的数组作为左子树,右边的数组作为右子树,重复上一步. 读完就知道是递归了. 这个题真尼玛恶心,对JavaScript的友好度简直为0,用Js的可以直接放弃了. function TreeNode(val) { this.val = val this.left = this.right = null } var constructMaximumBinaryTree = function…

Given an integer array with no duplicates. A maximum tree building on this array is defined as follow: The root is the maximum number in the array. The left subtree is the maximum tree constructed from left part subarray divided by the maximum number…

［抄题］: Given an integer array with no duplicates. A maximum tree building on this array is defined as follow: The root is the maximum number in the array. The left subtree is the maximum tree constructed from left part subarray divided by the maximum…

题目: Given an integer array with no duplicates. A maximum tree building on this array is defined as follow: The root is the maximum number in the array. The left subtree is the maximum tree constructed from left part subarray divided by the maximum nu…

题目如下: Given an integer array with no duplicates. A maximum tree building on this array is defined as follow: The root is the maximum number in the array. The left subtree is the maximum tree constructed from left part subarray divided by the maximum…

作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 递归 日期 题目地址:https://leetcode.com/problems/maximum-binary-tree/description/ 题目描述 Given an integer array with no duplicates. A maximum tree building on this array is defined as fol…

网址:https://leetcode.com/problems/maximum-binary-tree/ 参考: https://leetcode.com/problems/maximum-binary-tree/discuss/106146/C%2B%2B-O(N)-solution 我自己的做法是依照题意的逻辑,逐一递归的做法. O(n2) /** * Definition for a binary tree node. * struct TreeNode { * int val; * T…

Given an integer array with no duplicates. A maximum tree building on this array is defined as follow: The root is the maximum number in the array. The left subtree is the maximum tree constructed from left part subarray divided by the maximum number…

用一个整型数组构建一个二叉树,根结点是数组中的最大值,左右子树分别是根结点的值在数组中左右两边的部分. 分析,这是二叉树中比较容易想到的问题了,直接使用递归就行了,代码如下: class Solution(object): def constructMaximumBinaryTree(self, nums): """ :type nums: List[int] :rtype: TreeNode """ if not nums: return No…

每次找到数组中的最大值,然后递归的构建左右树 public TreeNode constructMaximumBinaryTree(int[] nums) { if (nums.length==0) return null; return builder(nums,0,nums.length-1); } public TreeNode builder(int[] nums,int sta,int end) { /* 思路就是每次找到最大值,然后分为两个子数组递归构建左右树 */ if (sta>…