Write a SQL query to rank scores. If there is a tie between two scores, both should have the same ranking. Note that after a tie, the next ranking number should be the next consecutive integer value. In other words, there should be no "holes" be…

Write a SQL query to rank scores. If there is a tie between two scores, both should have the same ranking. Note that after a tie, the next ranking number should be the next consecutive integer value. In other words, there should be no "holes" be…

Write a SQL query to rank scores. If there is a tie between two scores, both should have the same ranking. Note that after a tie, the next ranking number should be the next consecutive integer value. In other words, there should be no "holes" be…

做到这题时卡了不少时间,参考了别人的解法,觉得挺不错的,还挺巧妙. SELECT s2.Score,s1.Rank From ( SELECT S1.Score, COUNT(*) as Rank FROM (SELECT DISTINCT Score from Scores) as S1, (SELECT DISTINCT Score from Scores) as S2 Where S1.Score<=S2.Score Group By S1.Score ) s1 ,Scores s2 WH…

Write a SQL query to rank scores. If there is a tie between two scores, both should have the same ranking. Note that after a tie, the next ranking number should be the next consecutive integer value. In other words, there should be no "holes" be…

Write a SQL query to rank scores. If there is a tie between two scores, both should have the same ranking. Note that after a tie, the next ranking number should be the next consecutive integer value. In other words, there should be no "holes" be…

Write a SQL query to rank scores. If there is a tie between two scores, both should have the same ranking. Note that after a tie, the next ranking number should be the next consecutive integer value. In other words, there should be no "holes" be…

Write a SQL query to rank scores. If there is a tie between two scores, both should have the same ranking. Note that after a tie, the next ranking number should be the next consecutive integer value. In other words, there should be no "holes" be…

Write a SQL query to rank scores. If there is a tie between two scores, both should have the same ranking. Note that after a tie, the next ranking number should be the next consecutive integer value. In other words, there should be no "holes" be…

Score 很好得到: select Score from Scores order by Score desc; 要得到rank, 可以通过比较比当前Score 大的Score 的个数得到: select Score, (select count(distinct Score) from Scores where Score>=s.Score) Rank where Scores s order by Score desc; 或者: select s.Score ,count(distinct…

题目链接    https://leetcode.com/problems/rank-scores/description/ 题意:对所有的分数按照降序进行排序,查询出分数和排名,排名相同的输出相同名次 此种解法在leetcode中未通过,看错误提示,好像是数据的精确度问题,不知道为什么. 附上一个通过的(mysql):https://blog.csdn.net/travel_1/article/details/51589706 思路: 1.首先查出 不重复的所有分数排名 select dist…

问题描述 解决方案 select sc.Score, (select count(*) from (select distinct Score from Scores ) ds where ds.Score>= sc.Score ) Rank from Scores sc order by Score desc…

终于将LeetCode的免费题刷完了,真是漫长的第一遍啊,估计很多题都忘的差不多了,这次开个题目汇总贴,并附上每道题目的解题连接,方便之后查阅吧~ 477 Total Hamming Distance 44.10% Meidum 475 Heaters  30.20% Easy 474 Ones and Zeroes  34.90% Meidum 473 Matchsticks to Square  31.80% Medium 472 Concatenated Words 29.20% Hard…

请点击页面左上角 -> Fork me on Github 或直接访问本项目Github地址:LeetCode Solution by Swift    说明:题目中含有$符号则为付费题目. 如:[Swift]LeetCode156.二叉树的上下颠倒 $ Binary Tree Upside Down 请下拉滚动条查看最新 Weekly Contest!!! Swift LeetCode 目录 | Catalog 序        号 题名Title 难度     Difficulty  两数之…

All LeetCode Questions List(Part of Answers, still updating) 题目汇总及部分答案(持续更新中) Leetcode problems classified by company 题目按公司分类(Last updated: October 2, 2017) .   Top Interview Questions # Title Difficulty Acceptance 1 Two Sum Medium 17.70% 2 Add Two N…

终于将LeetCode的免费题刷完了,真是漫长的第一遍啊,估计很多题都忘的差不多了,这次开个题目汇总贴,并附上每道题目的解题连接,方便之后查阅吧~ 如果各位看官们,大神们发现了任何错误,或是代码无法通过OJ,或是有更好的解法,或是有任何疑问,意见和建议的话,请一定要在对应的帖子下面评论区留言告知博主啊(如果不方便注册博客园的话,可以下载下文提到的APP,在Feedback中给博主发邮件交流哈),同时也请大家踊跃地,大量地,盲目地提供各个题目的follow up一起讨论哈,多谢多谢,祝大家刷得愉快…

175. Combine Two Tables https://leetcode.com/problems/combine-two-tables/description/ Description Person 表: Column Name Type PersonId int FirstName varchar LastName varchar Address 表: Column Name Type AddressId int PersonId int City varchar State var…

Combine Two Tables # Write your MySQL query statement below Select p.FirstName, p.LastName, a.City, a.State from Person p left join Address a on p.PersonId = a.PersonId Consecutive Numbers # Write your MySQL query statement below select distinct num…

一.Rank Scores Write a SQL query to rank scores. If there is a tie between two scores, both should have the same ranking. Note that after a tie, the next ranking number should be the next consecutive integer value. In other words, there should be no "…

175. Combine Two Tables 使用外连接即可. # Write your MySQL query statement below select FirstName, LastName, City, State from Person left outer join Address on Person.PersonId = Address.PersonId; # Write your MySQL query statement below select p.FirstName,…

Combine Two Tables Table: Person +-------------+---------+ | Column Name | Type | +-------------+---------+ | PersonId | int | | FirstName | varchar | | LastName | varchar | +-------------+---------+ PersonId is the primary key column for this table.…

175 Combine Two Tables 题目:左连接Person表和Address表. select FirstName,LastName,City,State from Person p left join Address a on p.PersonId=a.PersonId; 7个case耗时1001ms(注意耗时多次提交会不同,一般相差不大,偶尔也有相差大的)   --2015/1/11 176 Second Highest Salary 题目:写一条sql语句查询Employee …

题目从难到易记录.解题过程中,如果不太熟悉,可以将题目中的表自己手动录入到自己的数据库中,就方便学习,测试. 185. Department Top Three Salaries 要求就是查询出每个部门工资在前三的人.题意值得注意的一点就是,要求找出的是工资数前三的人,而不是工资最高的前三位.区别就是前者查询出来的人可能大于3,而后者最大只能为3. 最终答案: select b.Name Department,a.Name Employee,a.Salary from (select Name,…

[175]Combine Two Tables (2018年11月23日,开始集中review基础) Table: Person +-------------+---------+ | Column Name | Type | +-------------+---------+ | PersonId | int | | FirstName | varchar | | LastName | varchar | +-------------+---------+ PersonId is the pr…

只用于个人的学习和总结. 178. Rank Scores 一.表信息 二.题目信息 对上表中的成绩由高到低排序,并列出排名.当两个人获得相同分数时,取并列名次,且名词中无断档. Write a SQL query to rank scores. If there is a tie between two scores, both should have the same ranking. Note that after a tie, the next ranking number should…

该脚本的目的:获取博客的排名和积分,将抓取时间,排名,积分存入数据库,然后把最近的积分和排名信息进行绘图,查看积分或者排名的变化情况. 整个脚本的流程:是利用python3来编写,利用selnium获取网页的信息,使用re正则表达式解析积分score和排名rank,用pymysql连接mysql数据库,最后利用matplotlib进行绘图. 首先创建db: xiaoshitou 创建表blog_rank: CREATE TABLE `blog_rank` ( `id` int(11) NOT N…

http://blog.csdn.net/pipisorry/article/details/48579435 海量数据挖掘Mining Massive Datasets(MMDs) -Jure Leskovec courses学习笔记之链接分析:PageRank算法 链接分析与PageRank {大图分析the Analysis of Large Graphs} how the class fits together 图数据的例子 社交网络Social Networks(Facebook so…

LeetCode:数据库技术[175-178] LeetCode已经刷完200道题目,但这只是开始,下一段时间,仍然把刷题作为重点,争取再次完成200道,本篇博客将会带大家熟悉一些数据库面试题,从简单到复杂,并且会把相关知识点全部阐述一下. 175.组合两个表 题目描述 表1: Person +-------------+---------+ | 列名 | 类型 | +-------------+---------+ | PersonId | int | | FirstName | varcha…

SQL查询练习一(From LeetCode) 1 select name,population,area 2 from World 3 where area > 3000000 or population > 25000000   3.判断是否是三角形(E) 思路,使用case when进行搭配,使用三角形定义进行判断x+y>z,x+z>y,y+z>x 1 select x,y,z, 2 case 3 when x+y>z and y+z>x and x+z&g…

大四已经接近一半了,下学期就要准备找工作实习了.为了自己能找到一份比较满意的实习,今天开始要刷一下题目.今天就刷 MySQL 语言.以下就是我今天刷的题目.大家也可以去 leetcode 注册一个账号来刷一下题目.里面有很多的算法题. 第一题:编写一个 SQL 查询,满足条件:无论 person 是否有地址信息,都需要基于上述两表提供 person 的以下信息:FirstName, LastName, City, State 表1: Person +-------------+---------…