题目传送门 /* 二分查找/暴力:先埃氏筛选预处理,然后暴力对于每一行每一列的不是素数的二分查找最近的素数,更新最小值 */ #include <cstdio> #include <cstring> #include <algorithm> using namespace std; ; ; const int INF = 0x3f3f3f3f; int a[MAXN][MAXN]; int mn_r[MAXN]; int mn_c[MAXN]; bool is_prim…

Can you find it? Time Limit: 10000/3000 MS (Java/Others)    Memory Limit: 32768/10000 K (Java/Others)Total Submission(s): 17036    Accepted Submission(s): 4337 Problem Description Give you three sequences of numbers A, B, C, then we give you a number…

what the fuck! Description 现在有一家公司有nnn个员工(nnn为奇数),他们的工资发放是基本工资+提成,现在这家公司计划再招一批人.要写一篇招聘启事,但是对于这个招聘启事中的薪资具体要写多少犯愁了. 规定招聘启事中薪资为nnn个工人中工资的中位数,为了能更快的招到人,招聘启事中写的薪资越大越好. 现在给出每个人的基本工资,以及可以用来发工资的总钱,你可以自由分配他们的提成(给出的钱可以不用完),让你求出最大的中位数.(保证有答案) Input 第一行两个整数n,sn,…

题目传送门 /* 题意:给出一个数,问是否有ai + bj + ck == x 二分查找:首先计算sum[l] = a[i] + b[j],对于q,枚举ck,查找是否有sum + ck == x */ #include <cstdio> #include <algorithm> #include <cmath> using namespace std; typedef long long ll; ; const int INF = 0x3f3f3f3f; ll a[MA…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2141 题目大意:查找是否又满足条件的x值. 这里简单介绍一个小算法,二分查找. /* x^2+6*x-7==y 输入y 求x 精确度为10^-5 0=<x<=10000 */ #include <iostream> #include <cstdio> using namespace std; int main (void) { double y; while(cin>…

Problem Description Give you three sequences of numbers A, B, C, then we give you a number X. Now you need to calculate if you can find the three numbers Ai, Bj, Ck, which satisfy the formula Ai+Bj+Ck = X.   Input There are many cases. Every data cas…

Give you three sequences of numbers A, B, C, then we give you a number X. Now you need to calculate if you can find the three numbers Ai, Bj, Ck, which satisfy the formula Ai+Bj+Ck = X. Input There are many cases. Every data case is described as foll…

Can you find it? Time Limit: 10000/3000 MS (Java/Others)    Memory Limit: 32768/10000 K (Java/Others)Total Submission(s): 9180    Accepted Submission(s): 2401 Problem Description Give you three sequences of numbers A, B, C, then we give you a number…

Give you three sequences of numbers A, B, C, then we give you a number X. Now you need to calculate if you can find the three numbers Ai, Bj, Ck, which satisfy the formula Ai+Bj+Ck = X. Input There are many cases. Every data case is described as foll…

题目传送门 题意:计算从1开始到第n个非完全平方数的开方和 分析:设第n个非完全平方数的值为a,x * x < a < (x+1) * (x+1),而且易得(tmp = sqrt (a) ) == x,a之前的非完全平方数的个数为a - tmp,所以可以二分查找a - tmp == n的a,然后模拟一下能计算出前a个数的开方和 收获:二分查找是个好方法 代码: /************************************************ * Author :Running…