1. 原题链接 https://leetcode.com/problems/length-of-last-word/description/ 2. 题目要求 给定一个String类型的字符串,字符串中可能含有空格‘  ’.从字符串的末尾开始查找,找到第一个单词,该单词中间不能有空格,并返回其长度. 3. 解题思路 首先判断该字符串是否为空,为空直接返回 0: 否则,从尾部向前查找,使用两个while循环,第一个while循环用于过滤空格,当该位置不为空格时,跳出while循环: 然后进入第二个w…

扫描每个WORD的长度并记录即可. int lengthOfLast(const char *s) { //扫描统计每个word的长度 ; while (*s) { if (*s++ != ' ')//注意不管是否满足s都要++ len++; else if (*s && *s != ' ') len = ; } return len; }…

做法很巧妙.分成左右两个对应的部分,遇到左半部分则入栈,遇到右半部分则判断对应的左半部分是否在栈顶.注意最后要判断堆栈是否为空. bool isValid(const string& s) { string left = "([{"; string right = ")]}"; stack<char> stk; for (auto c : s) { if (left.find(c) != string::npos) { stk.push(c);…

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space cha…

Length of Last Word  Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence cons…

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space cha…

题目描述: Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-spa…

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space cha…

[ 问题: ] Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. 给你一个字符串,设法获取它最后一个单词的长度.假设这个单词不存在,则返回0. [ 分析 : ] A word is defined…

1. 原题链接 https://leetcode.com/problems/longest-common-prefix/description/ 2. 题目要求 给定一个字符串数组,让你求出该数组中所有字符串的最大公共前缀.例如{"qqwwee", "qqww", "qqfds"}的最大公共前缀为"qq",{"qqwwee", "qqww", "qqfds", &qu…