Truck History Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 18981   Accepted: 7321 Description Advanced Cargo Movement, Ltd. uses trucks of different types. Some trucks are used for vegetable delivery, other for furniture, or for brick…
Truck History 题目链接: http://acm.hust.edu.cn/vjudge/contest/124434#problem/E Description Advanced Cargo Movement, Ltd. uses trucks of different types. Some trucks are used for vegetable delivery, other for furniture, or for bricks. The company has its…
链接: http://poj.org/problem?id=1789 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=22010#problem/G Truck History Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 14950   Accepted: 5714 Description Advanced Cargo Movement, Ltd. uses…
Truck History Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 21518   Accepted: 8367 Description Advanced Cargo Movement, Ltd. uses trucks of different types. Some trucks are used for vegetable delivery, other for furniture, or for brick…
poj——Truck History Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 27703   Accepted: 10769 Description Advanced Cargo Movement, Ltd. uses trucks of different types. Some trucks are used for vegetable delivery, other for furniture, or for…
Description Advanced Cargo Movement, Ltd. uses trucks of different types. Some trucks are used for vegetable delivery, other for furniture, or for bricks. The company has its own code describing each type of a truck. The code is simply a string of ex…
题目链接:http://poj.org/problem?id=1789 Advanced Cargo Movement, Ltd. uses trucks of different types. Some trucks are used for vegetable delivery, other for furniture, or for bricks. The company has its own code describing each type of a truck. The code…
题意:距离定义为两个字符串的不同字符的位置个数.然后求出最小生成树. #include <algorithm> #include <cstdio> #include <cstring> using namespace std; const int N=2001; const int M=4000001; char code[N][10]; int f[N];//并查集 struct edge{ int u,v,w; }e[M]; int n,tot; void add(…
模板题 题目:http://poj.org/problem?id=1789 题意:有n个型号,每个型号有7个字母代表其型号,每个型号之间的差异是他们字符串中对应字母不同的个数d[ta,tb]代表a,b之间的差异数问1/Σ(to,td)d(to,td)最大值 prime: #include <iostream> #include<cstdio> #include<cstring> #include<cstdlib> #include<stack>…
题目链接:http://poj.org/problem?id=1789 大意: 不同字符串相同位置上不同字符的数目和是它们之间的差距.求衍生出全部字符串的最小差距. #include<stdio.h> #include<math.h> #include<algorithm> using namespace std; ; int cnt; int pre[MAXN]; ]; struct Edge { int from, to; int val; }edge[MAXN *…