Given two integers n and k, return all possible combinations of k numbers out of 1 ... n. For example,If n = 4 and k = 2, a solution is: [ [2,4], [3,4], [2,3], [1,2], [1,3], [1,4], ] 思路:遍历n以内的正整数,每个数有放入与不放入两种选择=>带回溯的递归 class Solution { public: vector…

Given two integers n and k, return all possible combinations of k numbers out of 1 ... n. For example,If n = 4 and k = 2, a solution is: [ [2,4], [3,4], [2,3], [1,2], [1,3], [1,4], ] 给两个数字n, k,返回所有由[1...n]中的k数字组合的可能解. 解法1: 递归 解法2: 迭代 C++: Recursion c…

Given two integers n and k, return all possible combinations of k numbers out of 1 ... n. For example, If n = 4 and k = 2, a solution is: [ [2,4], [3,4], [2,3], [1,2], [1,3], [1,4], ] class Solution(object): def combine(self, n, k): """ :ty…

题目: Given two integers n and k, return all possible combinations of k numbers out of 1 ... n. For example,If n = 4 and k = 2, a solution is: [ [2,4], [3,4], [2,3], [1,2], [1,3], [1,4], ] Hide Tags Backtracking  链接:  http://leetcode.com/problems/combi…

Given two integers n and k, return all possible combinations of k numbers out of 1 ... n. For example, If n = 4 and k = 2, a solution is: [ [2,4], [3,4], [2,3], [1,2], [1,3], [1,4], ] 做了好几个这种题了,就是 backtrack problem, 1小时做出,但不容易,各种小毛病. 我的程序蠢蠢的建立了一个 vec…

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Given two integers n and k, return all possible combinations of k numbers out of 1 ... n. Example: Input: n = 4, k = 2 Output: [ [2,4], [3,4], [2,3], [1,2], [1,3], [1,4], ] 题目…

题目: Given two integers n and k, return all possible combinations of k numbers out of 1 ... n. 解析:同求全部组合的过程一样,只是这里限制每个组合中元素的个数为k,求所有组合时并不限制元素个数. 若要排除重复的元素,则首先对所有元素进行排序. 代码: public static List<List<Integer>> getAllCombinations(int[] array,int k)…

https://leetcode.com/problems/combinations/ 沿用78题的思路 class Solution { public: void backTrack(vector<int> ans, vector<int> nums, vector<vector<int>>& res, int times,int k) { if(ans.size() == k) { res.push_back(ans); } else { for…

题目 Given two integers n and k, return all possible combinations of k numbers out of 1 ... n. For example, If n = 4 and k = 2, a solution is: [ [2,4], [3,4], [2,3], [1,2], [1,3], [1,4], ] 解答 用递归,对i-n求k个数的组合,先确定一个数j(其中i <= j <= n + 1 - k),然后对(i + 1)-n…