DZY loves collecting special strings which only contain lowercase letters. For each lowercase letter c DZY knows its value wc. For each special string s = s1s2... s|s| (|s| is the length of the string) he represents its value with a function f(s), wh…

Content 有一个长度为 \(n\) 的仅含小写字母的字符串 \(s\) 以及 26 个英文小写字母的价值 \(W_\texttt{a},W_\texttt{b},...,W_\texttt{z}\),请求出在后面插入 \(k\) 个小写字母后所能够获得的最大价值. 对于一个长度为 \(x\) 的字符串 \(s'\),它的价值为 \(\sum\limits_{i=1}^x i\times W_{s'_i}\). 数据范围:\(1\leqslant n\leqslant 1000,0\leqs…

B - DZY Loves Strings DZY loves collecting special strings which only contain lowercase letters. For each lowercase letter c DZY knows its value wc. For each special string s = s1s2... s|s|(|s| is the length of the string) he represents its value wit…

D - DZY Loves Strings 思路:感觉这种把询问按大小分成两类解决的问题都很不好想.. https://codeforces.com/blog/entry/12959 题解说得很清楚啦. #include<bits/stdc++.h> #define LL long long #define fi first #define se second #define mk make_pair #define PLL pair<LL, LL> #define PLI pai…

D. DZY Loves Strings 题目连接: http://codeforces.com/contest/444/problem/D Description DZY loves strings, and he enjoys collecting them. In China, many people like to use strings containing their names' initials, for example: xyz, jcvb, dzy, dyh. Once DZ…

B. DZY Loves Strings time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output DZY loves collecting special strings which only contain lowercase letters. For each lowercase letter c DZY knows its val…

题目链接: DZY Loves Partition Time Limit: 4000/2000 MS (Java/Others)     Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 323    Accepted Submission(s): 127 Problem Description DZY loves partitioning numbers. He wants to know whether it is…

题意:给你一个矩阵,每次选某一行或者某一列,得到的价值为那一行或列的和,然后该行每个元素减去p.问连续取k次能得到的最大总价值为多少. 解法: 如果p=0,即永远不减数,那么最优肯定是取每行或每列那个最大的取k次,所以最优解由此推出. 如果不管p,先拿,最后再减去那些行列交叉点,因为每个点的值只能取一次,而交叉点的值被加了两次,所以要减掉1次,如果取行A次,取列B次,那么最后答案为: res = dp1[A] + dp2[B] - B*(k-A)*p,可以细细体会一下后面那部分. 其中: dp1…

链接:http://codeforces.com/problemset/problem/447/D 题意:一个n*m的矩阵.能够进行k次操作,每次操作室对某一行或某一列的的数都减p,获得的得分是这一行或列原来的数字之和.求N次操作之后得到的最高得分是多少. 思路:首先分别统计每行和每列的数字和. 进行的k次操作中,有i次操作是对行进行操作,剩余k-i次操作是对列进行操作. 首先在操作中忽略每次操作中行对列的影响,然后计算列的时候,最后能够计算出,总共的影响是i*(k-i)*p. 找出对于每一个i…

B. DZY Loves Strings time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output DZY loves collecting special strings which only contain lowercase letters. For each lowercase letter c DZY knows its val…