Dynamic Problem Scoring 思路: 水题: 代码: #include <cstdio> #include <cstring> #include <iostream> #include <algorithm> using namespace std; #define maxn 130 ],ac[],cnt,all,last1,last2; ][]; inline void in(int &now) { ;now=; char Cge…
地址:http://codeforces.com/contest/807/problem/D 题目: D. Dynamic Problem Scoring time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Vasya and Petya take part in a Codeforces round. The round las…
D. Dynamic Problem Scoring time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Vasya and Petya take part in a Codeforces round. The round lasts for two hours and contains five problems. For th…
[题目链接]:http://codeforces.com/contest/807/problem/D [题意] 给出n个人的比赛信息; 5道题 每道题,或是没被解决->用-1表示; 或者给出解题的所用的时间; (每道题的分数与解决率有关,越高,分越低); 然后有个人想利用这个特点,注册很多个账号; 试图改变每道题的解决率,以期让自己的分数大于某个人; 如果这个人没有解决某道题的话; 那些新加入的人也不能解决那道题. 问最少需要注册多少个账号才能让你的分数大于某个人; [题解] 顺序枚举加入了多少…
题目链接:http://codeforces.com/contest/807/problem/D 题意:对于动态计分的 Codeforces Round ,已知每题的 score 是根据 Round 参加人数和该题过题人数计算,两者之比结合上图得出该题的分数.某人在该题的得分为 score*(1−t/250) 其中 t 表示通过该题的时间. 已知参加该场比赛的所有参加者的过题情况(包括 Vasya 和 Petya),问如何通过增加新的参赛者(尽量少),使得 Vasya 的最终得分高于 Petya…
Dynamic Ranking 思路: 可持久化树状数组: 代码: #include <bits/stdc++.h> using namespace std; #define maxn 10005 #define maxtot maxn*600 struct QueryType { int l,r,k; ]; }; struct QueryType qu[maxn]; ],root[maxn]; ],numl,posr[],numr,lc[maxtot]; int rc[maxtot],dis…
E. Sign on Fence time limit per test 4 seconds memory limit per test 256 megabytes input standard input output standard output Bizon the Champion has recently finished painting his wood fence. The fence consists of a sequence of n panels of 1 meter w…
A. Andryusha and Socks time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Andryusha is an orderly boy and likes to keep things in their place. Today he faced a problem to put his socks in the…
812B - Sagheer, the Hausmeister 思路: 搜索: 代码: #include <cstdio> #include <cstring> #include <iostream> #include <algorithm> using namespace std; #define maxn 20 #define maxm 105 #define INF 0x7fffffff ],num[maxn],ans=INF,k,sum[maxn],…
812A - Sagheer and Crossroads 思路: 模拟: 代码: #include <cstdio> #include <cstring> #include <iostream> #include <algorithm> using namespace std; #define Yes {puts("YES\n");return 0;} ][]; int main() { ;i<=;i++) { scanf(],&…