Given an array of integers, find a contiguous subarray which has the largest sum. 首先 當題目涉及到求最大最小值時,最初的比較數字就應當設置爲INT_MAX或INT_MIN,更爲安全. <limits.h>中有INT_MAX和INT_MIN的宏定義可直接使用. 或者自行定義宏 #define INT_MAX 0x7fffffff #define INT_MIN 0x80000000 INT_MAX = INT_M…
Minimum Subarray 原题链接: http://lintcode.com/zh-cn/problem/minimum-subarray/# Given an array of integers, find the subarray with smallest sum. Return the sum of the subarray. 注意 The subarray should contain at least one integer. 样例 For [1, -1, -2, 1], r…
Given an array of integers, find the subarray with smallest sum. Return the sum of the subarray. Have you met this question in a real interview? Yes Example For [1, -1, -2, 1], return -3 Note The subarray should contain at least one integer. public c…
题目: 最小子数组 给定一个整数数组,找到一个具有最小和的子数组.返回其最小和. 样例 给出数组[1, -1, -2, 1],返回 -3 注意 子数组最少包含一个数字 解题: 和最大子数组 ,差不多的,动态规划的还是可以继续用的 Java程序: public class Solution { /** * @param nums: a list of integers * @return: A integer indicate the sum of minimum subarray */ publ…
题目:Given a string S and a string T, find the minimum window in S which will contain all the characters in T in complexity O(n). For example,S = "ADOBECODEBANC"T = "ABC" Minimum window is "BANC". Note:If there is no such windo…
题目:Given a string S and a string T, find the minimum window in S which will contain all the characters in T in complexity O(n). For example,S = "ADOBECODEBANC"T = "ABC" Minimum window is "BANC". Note:If there is no such windo…
题目: Given a string S and a string T, find the minimum window in S which will contain all the characters in T in complexity O(n). For example, S = "ADOBECODEBANC" T = "ABC" Minimum window is "BANC". Note: If there is no such w…
这道题目一眼就能看出是送分题,当然在这里也不谈高难度的实现逻辑,肯定有同学会想直接用自带函数实现不就可以了吗? 对的,就是这么简单,然而今天的重点是如何把代码简写到最短. 本文章将带你把代码长度从 一步步走到 Let's get started 首先要说明的是LintCode的代码长度是按照每一个位来计算的,因此代码中所有的空格,备注,换行等都会占用长度 首先初始化代码窗口是这样的 /** * @param character: a character * @return: a characte…
