简单排序.题意较长. #include<cstdio> #include<cstring> #include<cmath> #include<queue> #include<vector> #include<string> #include<stack> #include<map> #include<algorithm> using namespace std; struct X { int id;…

题意: 输入三个正整数N,L,H(N<=1E5,L>=60,H<100,H>L),分别代表人数,及格线和高水平线.接着输入N行数据,每行包括一个人的ID,道德数值和才能数值.一个人的道德和才能都不低于H时为圣人,道德不低于H才能不低于L时为贵族,道德和才能都不低于L且道德不低于才能时为愚者,道德和才能都不低于L且道德低于才能时为小人(圣人优先判断,圣人的才能可以高于道德).分别在自己的所在的群体内排序,依照道德才能总和降序排序,第二优先为才能的数值降序,第三优先为id的升序.按照题…

题目信息 1062. Talent and Virtue (25) 时间限制200 ms 内存限制65536 kB 代码长度限制16000 B About 900 years ago, a Chinese philosopher Sima Guang wrote a history book in which he talked about people's talent and virtue. According to his theory, a man being outstanding i…

1062 Talent and Virtue (25 分)   About 900 years ago, a Chinese philosopher Sima Guang wrote a history book in which he talked about people's talent and virtue. According to his theory, a man being outstanding in both talent and virtue must be a "sage…

/* L (>=60), the lower bound of the qualified grades -- that is, only the ones whose grades of talent and virtue are both not below this line will be ranked; and H (<100), the higher line of qualification ,those with both grades not below this line…

About 900 years ago, a Chinese philosopher Sima Guang wrote a history book in which he talked about people's talent and virtue. According to his theory, a man being outstanding in both talent and virtue must be a "sage(圣人)"; being less excellent…

难得的一次ac 题目意思直接,方法就是对virtue talent得分进行判断其归属类型,用0 1 2 3 4 表示 不合格 sage noblemen foolmen foolmen 再对序列进行排序 优先级  类型>total grade>virtue>id #include<iostream> #include<stdio.h> #include<string.h> #include<algorithm> using namespac…

水题,分组排序即可. #include <iostream> #include <cstdio> #include <algorithm> #include <string.h> using namespace std; /* 太水水水... */ +; int cnt1,cnt2,cnt3,cnt4; struct Node{ int id; int tot; int vir; int tal; bool operator<(const Node t…

简单题. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<map> #include<queue> #include<stack> #include<algorithm> using namespace std; +]; ,sum2; int n; int main() { scanf("%d&q…

判断一棵二叉树是否完全二叉树. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<map> #include<queue> #include<stack> #include<algorithm> using namespace std; int n,root; ; struct Node { int left…

简单DFS. #include<cstdio> #include<cstring> #include<cmath> #include<algorithm> #include<map> #include<queue> #include<stack> #include<vector> using namespace std; ; int n,m; vector<int>g[maxn]; int ans[…

简单题. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<map> #include<stack> #include<queue> #include<string> #include<algorithm> using namespace std; +; struct Node { ]; ]; ]…

模拟题.坑点较多. #include<iostream> #include<cstring> #include<cmath> #include<algorithm> #include<cstdio> #include<map> #include<queue> #include<string> #include<stack> #include<vector> using namespace…

简单模拟. #include<iostream> #include<cstring> #include<cmath> #include<algorithm> #include<cstdio> #include<map> #include<queue> #include<string> #include<stack> #include<vector> using namespace std…

简单题. #include<iostream> #include<cstring> #include<cmath> #include<algorithm> #include<cstdio> #include<map> #include<queue> #include<string> #include<stack> #include<vector> using namespace std;…

双指针. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<map> #include<queue> #include<stack> #include<string> #include<algorithm> using namespace std; +; long long a[maxn]; in…

暴力. #include<cstdio> #include<cstring> #include<algorithm> using namespace std; ]; int ans,len,sum; void check(int a,int b) { if(s[a]!=s[b]) return; ; ; ,right=b+; ||right>=len||s[left]!=s[right])) left--,right++,sum=sum+; ans=max(ans…

简单模拟. #include<iostream> #include<cstring> #include<cmath> #include<algorithm> #include<cstdio> #include<map> #include<queue> using namespace std; struct X { long long hh,mm,ss; long long len; long long st,ml; }s[…

并查集判断连通性. #include<iostream> #include<cstring> #include<cmath> #include<algorithm> #include<cstdio> #include<map> using namespace std; ; struct Edge { int u,v; }e[maxn*maxn]; int n,m,k; int f[maxn]; int Find(int x) { if…

简单排序题. 注意:分数相同的人排名相同. #include<iostream> #include<cstring> #include<cmath> #include<algorithm> #include<cstdio> #include<map> using namespace std; struct X { int k; int id; int f1,f2,f3,f4; ]; }s[]; int n,m; map<int,…

简单模拟. #include<iostream> #include<cstring> #include<cmath> #include<algorithm> #include<cstdio> using namespace std; ],b[],c[]; int k; int main() { ;i<=;i++) a[i]=b[i]=c[i]=; ; scanf("%d",&k); ;i<=k;i++) {…

简单DP. 注意:If all the K numbers are negative, then its maximum sum is defined to be 0, and you are supposed to output the first and the last numbers of the whole sequence. #include<iostream> #include<cstring> #include<cmath> #include<al…

Given a sequence of K integers { N1, N2, ..., NK }. A continuous subsequence is defined to be { Ni, Ni+1, ..., Nj } where 1 <= i <= j <= K. The Maximum Subsequence is the continuous subsequence which has the largest sum of its elements. For examp…

简单题.模拟一下即可. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<map> #include<queue> #include<stack> #include<algorithm> using namespace std; ; int a[maxn],b[maxn],n; int main() { sc…

入栈顺序为先序遍历,出栈顺序为中序遍历. #include<cstdio> #include<cstring> #include<cmath> #include<algorithm> #include<stack> using namespace std; +; const int INF=0x7FFFFFFF; int n,tot; int Preorder[maxn],Inorder[maxn],Postorder[maxn]; int AP…

简单题. #include<iostream> #include<cstring> #include<cmath> #include<algorithm> #include<cstdio> #include<map> #include<queue> #include<vector> using namespace std; ; struct X { string name; string sex; string…

Excel can sort records according to any column. Now you are supposed to imitate this function. Input Specification: Each input file contains one test case. For each case, the first line contains two integers N (≤) and C, where N is the number of reco…

As an emergency rescue team leader of a city, you are given a special map of your country. The map shows several scattered cities connected by some roads. Amount of rescue teams in each city and the length of each road between any pair of cities are…

1062. Talent and Virtue (25) 时间限制 200 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Li About 900 years ago, a Chinese philosopher Sima Guang wrote a history book in which he talked about people's talent and virtue. According to his theory, a…

1062 Talent and Virtue (25 分) About 900 years ago, a Chinese philosopher Sima Guang wrote a history book in which he talked about people's talent and virtue. According to his theory, a man being outstanding in both talent and virtue must be a "sage(圣…