和hdu2888基本上一样的,也是求一个矩阵内的极值 #include<iostream> #include<cstring> #include<cstdio> #include<algorithm> #include<cmath> using namespace std; #define maxn 252 int n,b,q; ][],dpmin[maxn][maxn][][],val[maxn][maxn]; void ST(){ int k…

Check Corners Time Limit: 2000/10000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2377    Accepted Submission(s): 859 Problem Description Paul draw a big m*n matrix A last month, whose entries Ai,j are all intege…

Cornfields Time Limit: 1000MS   Memory Limit: 30000K Total Submissions:8623   Accepted: 4100 Description FJ has decided to grow his own corn hybrid in order to help the cows make the best possible milk. To that end, he's looking to build the cornfiel…

int main(){ ; i <= n; i++) ; j <= m; j++) { scanf("%d", &val[i][j]); dp[i][j][][] = val[i][j]; } ; ( << i) <= n; i++) { ; ( << j) <= m; j++) { && j == ) continue; ; row + ( << i) - <= n; row++) ; col…

就是求子矩阵中最大值与最小值的差... 板子都套不对的人.... #include <iostream> #include <cstdio> #include <sstream> #include <cstring> #include <map> #include <set> #include <vector> #include <stack> #include <queue> #include &…

Cornfields Time Limit:1000MS     Memory Limit:30000KB     64bit IO Format:%I64d & %I64u Submit Status Description FJ has decided to grow his own corn hybrid in order to help the cows make the best possible milk. To that end, he's looking to build the…

题目传送门 Cornfields Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 7963   Accepted: 3822 Description FJ has decided to grow his own corn hybrid in order to help the cows make the best possible milk. To that end, he's looking to build the c…

http://acm.hdu.edu.cn/showproblem.php?pid=2888 题意:给出一个n*m的矩阵,还有q个询问,对于每个询问有一对(x1,y1)和(x2,y2),求这个子矩阵中的最大值,和判断四个角有没有等于这个最大值的. 思路:二维RMQ模板题.注意内存卡的挺紧的. #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> using nam…

原题大意:原题链接 给定元素无重复数组,查询给定区间内元素是否连续 解体思路:由于无重复元素,所以如果区间内元素连续,则该区间内的最大值和最小值之差应该等于区间长度(r-l) 解法一:线段树(模板题) #include<cstdio> #include<algorithm> #define inf 0x3f3f3f3f using namespace std; ; int va,curmi,curma; *maxn],ma[*maxn]; void Build(int p,int…

<题目链接> <转载于 >>> > 题目大意: 给出一个N*M的矩阵,并且给出该矩阵上每个点对应的值,再进行Q次询问,每次询问给出代询问子矩阵的左上顶点和右下顶点,问该子矩阵的最大值是多少,并且判断该最值是否在该子矩阵的四个顶角上. 解题分析: 很明显求二维区间内的最值,需要用到二维RMQ,其中dp[i][j][k][l]表示左上角为(i,j),右下角为(i + 2 ^ k - 1, j + 2 ^ l - 1)这个矩形内的最值.注意这个四维数组不要开得太大,否则…