leetcode 561.Array Partition I-easy】的更多相关文章

题目描述 给定长度为 2n 的数组, 你的任务是将这些数分成 n 对, 例如 (a1, b1), (a2, b2), ..., (an, bn) ,使得从1 到 n 的 min(ai, bi) 总和最大. 示例 1: 输入: [1,4,3,2] 输出: 4 解释: n 等于 2, 最大总和为 4 = min(1, 2) + min(3, 4). 提示: n 是正整数,范围在 [1, 10000]. 数组中的元素范围在 [-10000, 10000]. 思路 分组之后min(ai, bi)的和最大…
Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), ..., (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible. Example 1: Input: [1,4,3,2] Output: 4 Explan…
Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), ..., (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible. Example 1: Input: [1,4,3,2] Output: 4 Explan…
题目要求 Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), ..., (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible. 题目分析及思路 题目给出一个含2n个整数的数组,要求拆成n对整数对,使得每个整…
Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), ..., (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible. Example 1: Input: [1,4,3,2] Output: 4 Explan…
题目: Given an array of 2n integers, your task is to group these integers into npairs of integer, say (a1, b1), (a2, b2), ..., (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible. Example 1: Input: [1,4,3,2] Output: 4 Exp…
561. Array Partition I[easy] Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), ..., (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible. Example 1: Inpu…
Question 561. Array Partition I Solution 题目大意是,给的数组大小是2n,把数组分成n组,每组2个元素,每个组取最小值,这样就能得到n个值,怎样分组才能使这n个数相加最小. 思路:有点田忌赛马的意思,肯定最大和第二大一组,取最小值即第二大的数,依次类推...这样就需要排序,隔一个取一个. Java实现: public int arrayPairSum(int[] nums) { Arrays.sort(nums); int total = 0; for (…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 排序 日期 题目地址:https://leetcode.com/problems/array-partition-i/#/description 题目描述 Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (…
题目描述:两句话发人深思啊.... Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), ..., (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible. 感觉题目的大致意思就是把数组分成很多个二元数组,对它…
Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), ..., (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible. Example 1: Input: [1,4,3,2] Output: 4 Explan…
Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), ..., (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible. Example 1: Input: [1,4,3,2] Output: 4 Explan…
原题: Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), ..., (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible. 解析: 数组分割1 给一组2n个整数,分割为n组,一组2个数,使min(a,b)…
Given an array of 2n integers, your task is to group these integers into n pairs of integer, say \((a_1, b_1), (a_2, b_2), ..., (a_n, b_n)\) which makes sum of \(min(a_i, b_i)\) for all \(i\) from \(1\) to \(n\) as large as possible. Example 1: Input…
Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), ..., (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible. Example 1: Input: [1,4,3,2] Output: 4 Explan…
package y2019.Algorithm.array; /** * @ProjectName: cutter-point * @Package: y2019.Algorithm.array * @ClassName: ArrayPairSum * @Author: xiaof * @Description: 561. Array Partition I * Given an array of 2n integers, your task is to group these integers…
leetcode - 35. Search Insert Position - Easy descrition Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the arr…
STL中的list就是一双向链表,可高效地进行插入删除元素. List 是 C++标准程式库 中的一个 类 ,可以简单视之为双向 连结串行 ,以线性列的方式管理物件集合.list 的特色是在集合的任何位置增加或删除元素都很快,但是不支持随机存取.list 是 C++标准程式库 提供的众多容器(container)之一,除此之外还有 vector .set.map.…等等.list 以模板方式实现(即泛型),可以处理任意型别的变量,包括使用者自定义的资料型态,例如:它可以是一个放置整数(int)型…
索引:[LeetCode] Leetcode 题解索引 (C++/Java/Python/Sql) Github: https://github.com/illuz/leetcode 038. Count and Say (Easy) 链接: 题目:https://leetcode.com/problems/Count-and-Say/ 代码(github):https://github.com/illuz/leetcode 题意: 数数.第一个是 1,第二个是数前一个数:1 个 1,就是 11…
[LeetCode]86. Partition List 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.me/ 题目地址:https://leetcode.com/problems/partition-list/description/ 题目描述: Given a linked list and a value x, partition it such that all no…
文章全部来自公众号:爱写bug 算法是一个程序的灵魂. Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), ..., (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible. 给定长度为 2n 的数组, 你的…
这是悦乐书的第262次更新,第275篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第129题(顺位题号是561).给定一个2n个整数的数组,你的任务是将这些整数分组为n对整数,比如说(a1,b1),(a2,b2),...,(an,bn),找出每对(ai, bi)中最小值,然后相加,使得其和最大.例如: 输入:[1,4,3,2] 输出:4 说明:n为2,对的最大总和为4 = min(1,2)+ min(3,4). 注意: n是正整数,其范围为[1,10000]. 数组…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/partition-array-into-three-parts-with-equal-sum/ 题目描述 Given an array A of integers, return true if and only if we can partition the array…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址: https://leetcode.com/problems/partition-array-into-disjoint-intervals/description/ 题目描述: Given an array A, partition it into two (contiguous) subarrays left and right so that: Every elemen…
Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), ..., (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible. Example 1: Input: [1,4,3,2] Output: 4 Explan…
题目如下: Given an integer array A, you partition the array into (contiguous) subarrays of length at most K.  After partitioning, each subarray has their values changed to become the maximum value of that subarray. Return the largest sum of the given arr…
题目如下: Given an array A of integers, return true if and only if we can partition the array into three non-emptyparts with equal sums. Formally, we can partition the array if we can find indexes i+1 < j with (A[0] + A[1] + ... + A[i] == A[i+1] + A[i+2]…
问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/3718 访问. 给定长度为 2n 的数组, 你的任务是将这些数分成 n 对, 例如 (a1, b1), (a2, b2), ..., (an, bn) ,使得从1 到 n 的 min(ai, bi) 总和最大. 输入: [1,4,3,2] 输出: 4 解释: n 等于 2, 最大总和为 4 = min(1, 2) + min(3, 4). 提示: n 是正整数,范…
1.题目描述 2.分析 按照题目要求,主要就是对数组进行排序 3.代码 int arrayPairSum(vector<int>& nums) { ; sort( nums.begin() , nums.end() ); ; i< nums.size(); i += ) { ans += nums[i]; } return ans; }…
原题链接 很水的一道题,就是数组内部交换. 水题就想着减少复杂度嘛,于是学到一种交换写法. class Solution { public: vector<int> sortArrayByParity(vector<int> &A) { int i = 0, j = A.size()-1; while (i < j) { if (A[i] & 0x01) { A[i] ^= A[j]; A[j] ^= A[i]; A[i] ^= A[j]; --j; } el…