Given a binary search tree and the lowest and highest boundaries as L and R, trim the tree so that all its elements lies in [L, R] (R >= L). You might need to change the root of the tree, so the result should return the new root of the trimmed binary…
Given a non-empty binary search tree and a target value, find the value in the BST that is closest to the target. Note: Given target value is a floating point. You are guaranteed to have only one unique value in the BST that is closest to the target.…
给定一个单元链表,元素按升序排序,将其转换为高度平衡的BST.对于这个问题,一个高度平衡的二叉树是指:其中每个节点的两个子树的深度相差不会超过 1 的二叉树.示例:给定的排序链表: [-10, -3, 0, 5, 9],则一个可能的答案是:[0, -3, 9, -10, null, 5]      0     / \   -3   9   /   / -10  5详见:https://leetcode.com/problems/convert-sorted-list-to-binary-sear…
给定一个单链表,其中的元素按升序排序,将其转换为高度平衡的二叉搜索树. 本题中,一个高度平衡二叉树是指一个二叉树每个节点 的左右两个子树的高度差的绝对值不超过 1. 示例: 给定的有序链表: [-10, -3, 0, 5, 9], 一个可能的答案是:[0, -3, 9, -10, null, 5], 它可以表示下面这个高度平衡二叉搜索树: 0 / \ -3 9 / / -10 5 class Solution { public: TreeNode* sortedListToBST(ListNod…
判断二叉搜索树的方法是: 中序遍历形成递增序列 //全局变量记录中序遍历产生的序列,因为要递归,所以要用全局变量 List<Integer> list = new ArrayList<>(); public boolean isValidBST(TreeNode root) { /* 这里要注意二叉搜索树的左子树的每个节点都要小于根节点,不只是左孩子,右子树也同样, 常犯的一个错误就是只是判断了左孩子和右孩子 正确方法是:中序遍历法,中序遍历之后的结果是一个递增序列 判断是否是二叉…
Level:   Medium 题目描述: Given a binary tree, determine if it is a valid binary search tree (BST). Assume a BST is defined as follows: The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of a node contain…
Given n, generate all structurally unique BST's (binary search trees) that store values 1...n. For example, Given n = 3, your program should return all 5 unique BST's shown below. 1 3 3 2 1 \ / / / \ \ 3 2 1 1 3 2 / / \ \ 2 1 2 3 confused what "{1,#,…
题目如下所示:返回的结果是一个Node的Vector: Given n, generate all structurally unique BST's (binary search trees) that store values 1...n. For example,Given n = 3, your program should return all 5 unique BST's shown below. 1 3 3 2 1 \ / / / \ \ 3 2 1 1 3 2 / / \ \ 2…
Level:   Medium 题目描述: Given n, how many structurally unique BST's (binary search trees) that store values 1 ... n? Example: Input: 3 Output: 5 Explanation: Given n = 3, there are a total of 5 unique BST's: 1 3 3 2 1 \ / / / \ \ 3 2 1 1 3 2 / / \ \ 2…
Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 二分递归转换 Hide Tags Tree Depth-first Search /** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode…