836. 矩形重叠 矩形以列表 [x1, y1, x2, y2] 的形式表示,其中 (x1, y1) 为左下角的坐标,(x2, y2) 是右上角的坐标. 如果相交的面积为正,则称两矩形重叠.需要明确的是,只在角或边接触的两个矩形不构成重叠. 给出两个矩形,判断它们是否重叠并返回结果. 示例 1: 输入:rec1 = [0,0,2,2], rec2 = [1,1,3,3] 输出:true 示例 2: 输入:rec1 = [0,0,1,1], rec2 = [1,0,2,1] 输出:false 提示…

836. 矩形重叠 矩形以列表 [x1, y1, x2, y2] 的形式表示,其中 (x1, y1) 为左下角的坐标,(x2, y2) 是右上角的坐标. 如果相交的面积为正,则称两矩形重叠.需要明确的是,只在角或边接触的两个矩形不构成重叠. 给出两个矩形,判断它们是否重叠并返回结果. 示例 1: 输入:rec1 = [0,0,2,2], rec2 = [1,1,3,3] 输出:true 示例 2: 输入:rec1 = [0,0,1,1], rec2 = [1,0,2,1] 输出:false 提示…

题目链接:https://leetcode-cn.com/problems/rectangle-overlap/ 矩形以列表 [x1, y1, x2, y2] 的形式表示,其中 (x1, y1) 为左下角的坐标,(x2, y2) 是右上角的坐标. 如果相交的面积为正,则称两矩形重叠.需要明确的是,只在角或边接触的两个矩形不构成重叠. 给出两个矩形,判断它们是否重叠并返回结果. 示例 1: 输入:rec1 = [0,0,2,2], rec2 = [1,1,3,3]输出:true示例 2: 输入:r…

A rectangle is represented as a list [x1, y1, x2, y2], where (x1, y1) are the coordinates of its bottom-left corner, and (x2, y2) are the coordinates of its top-right corner. Two rectangles overlap if the area of their intersection is positive.  To b…

A rectangle is represented as a list [x1, y1, x2, y2], where (x1, y1) are the coordinates of its bottom-left corner, and (x2, y2) are the coordinates of its top-right corner. Two rectangles overlap if the area of their intersection is positive.  To b…

［抄题］: A rectangle is represented as a list [x1, y1, x2, y2], where (x1, y1) are the coordinates of its bottom-left corner, and (x2, y2) are the coordinates of its top-right corner. Two rectangles overlap if the area of their intersection is positive.…

Find the total area covered by two rectilinear rectangles in a2D plane. Each rectangle is defined by its bottom left corner and top right corner as shown in the figure. Assume that the total area is never beyond the maximum possible value of int. Cre…

Given a collection of intervals, find the minimum number of intervals you need to remove to make the rest of the intervals non-overlapping. Note: You may assume the interval's end point is always bigger than its start point. Intervals like [1,2] and…

Two images A and B are given, represented as binary, square matrices of the same size.  (A binary matrix has only 0s and 1s as values.) We translate one image however we choose (sliding it left, right, up, or down any number of units), and place it o…

有两种方式. 1. 排除法,排除四种不可能重叠的情况就是了. public static boolean IsOverlap( Rectangle rect1, Rectangle rect2 ){ float x1 = rect1.x, y1 = rect1.y, w1 = rect1.width, h1 = rect1.height; float x2 = rect2.x, y2 = rect2.y, w2 = rect2.width, h2 = rect2.height; return !…