最小公倍数 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 69793    Accepted Submission(s): 38394 Problem Description 给定两个正整数,计算这两个数的最小公倍数.   Input 输入包含多组测试数据,每组只有一行,包括两个不大于1000的正整数.   Output 对于每个测试用…

#include <cstdio> int gcd(int a,int b) { ) return a; else return gcd(b,a%b); } int main() { int m,n; while (scanf("%d%d",&m,&n)!=EOF) { printf("%d\n",m*n/gcd(m,n)); } ; } …

gcd模板: __int64 gcd(__int64 a,__int64 b) { retur b==0?a:gcd(b,a%b); } 1108: #include<iostream> #include<cstdio> using namespace std; __int64 gcd(__int64 a,__int64 b) { return b==0?a:gcd(b,a%b); } int main() { int a,b; while(scanf("%d%d&quo…

水题,只是想借此记一下gcd函数的模板 #include<cstdio> int gcd(int m,int n){return n?gcd(n,m%n):m;} int main() { int n,m,t; scanf("%d",&t); while(t--){ scanf("%d%d",&m,&n); ) printf("NO\n"); else printf("YES\n"); }…

欢迎参加——BestCoder周年纪念赛(高质量题目+多重奖励) 相遇周期 Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2465    Accepted Submission(s): 1236 Problem Description 2007年3月26日,在中俄两国元首的见证下,中国国家航天局局长孙来燕与俄罗斯联邦航天局局长别尔米诺夫…

Chinese remainder theorem again Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Problem Description 我知道部分同学最近在看中国剩余定理,就这个定理本身,还是比较简单的:假设m1,m2,…,mk两两互素,则下面同余方程组:x≡a1(mod m1)x≡a2(mod m2)…x≡ak(mod mk)在0<=<m1m2…mk内有唯一…

HDU 1000 A + B Problem  I/O HDU 1001 Sum Problem  数学 HDU 1002 A + B Problem II  高精度加法 HDU 1003 Maxsum  贪心 HDU 1004 Let the Balloon Rise  字典树,map HDU 1005 Number Sequence  求数列循环节 HDU 1007 Quoit Design  最近点对 HDU 1008 Elevator  模拟 HDU 1010 Tempter of th…

传送门:http://acm.hdu.edu.cn/showproblem.php?pid=1019 Least Common Multiple Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 61592    Accepted Submission(s): 23486 Problem Description The least comm…

Problem Description 我知道部分同学最近在看中国剩余定理,就这个定理本身,还是比较简单的: 假设m1,m2,-,mk两两互素,则下面同余方程组: x≡a1(mod m1) x≡a2(mod m2) - x≡ak(mod mk) 在0<=<m1m2-mk内有唯一解. 记Mi=M/mi(1<=i<=k),因为(Mi,mi)=1,故有二个整数pi,qi满足Mipi+miqi=1,如果记ei=Mi/pi,那么会有: ei≡0(mod mj),j!=i ei≡1(mod m…

HDU 4627 Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u   Description There are many unsolvable problem in the world.It could be about one or about zero.But this time it is about bigger number. Given an integer n(2 <=…