HDU 1852 Beijing 2008 数论】的更多相关文章

题目地址: http://acm.hdu.edu.cn/showproblem.php?pid=1852 这道题和HDU1452类似. 题意:给你一个n.k,让你求2008^n所有因子的和(包括1和本身)%k,得到m,然后输出2008^m%k. 题解:看我HDU1452题,这里有一点需要注意的是: s=(2^(3n+1)-1)(251^(n+1)-1)/250 因为gcd(250,k)不一定等于1,所以不能用求逆元的方法求解, 而k很小,所以我们可以将k乘以250,然后在进行,最后结果一定可以整…
HDU 1005 Number Sequence(数论) Problem Description: A number sequence is defined as follows:f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7. Given A, B, and n, you are to calculate the value of f(n).   Input The input consists of multipl…
Beijing 2008 Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/65535 K (Java/Others)Total Submission(s): 741    Accepted Submission(s): 291 Problem Description As we all know, the next Olympic Games will be held in Beijing in 2008. So the…
Least Common Multiple (HDU - 1019) [简单数论][LCM][欧几里得辗转相除法] 标签: 入门讲座题解 数论 题目描述 The least common multiple (LCM) of a set of positive integers is the smallest positive integer which is divisible by all the numbers in the set. For example, the LCM of 5, 7…
七夕节 (HDU - 1215) [简单数论][找因数] 标签: 入门讲座题解 数论 题目描述 七夕节那天,月老来到数字王国,他在城门上贴了一张告示,并且和数字王国的人们说:"你们想知道你们的另一半是谁吗?那就按照告示上的方法去找吧!" 人们纷纷来到告示前,都想知道谁才是自己的另一半.告示如下: 数字N的因子就是所有比N小又能被N整除的所有正整数,如12的因子有1,2,3,4,6. 你想知道你的另一半吗? Input 输入数据的第一行是一个数字T(1<=T<=500000)…
题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=1852 题目大意: 求2008^n的所有因子和m对k取余,然后求2008^m对k取余. 解题思路: 首先将2008因式分解,2008 = 2^3 * 251 所以2008^n = 2^(3n) * 251^(n) 因子和m =(2^(3n+1)- 1) * (251^(n+1) - 1)/ 250 m需要对k取余数.由于余数k和250可能不互质,也就是没有逆元存在,那么需要用到通用公式: 所以可以用…
As we all know, the next Olympic Games will be held in Beijing in 2008. So the year 2008 seems a little special somehow. You are looking forward to it, too, aren't you? Unfortunately there still are months to go. Take it easy. Luckily you meet me. I…
H - Visible Trees Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 2841 Description There are many trees forming a m * n grid, the grid starts from (1,1). Farmer Sherlock is standing at (0,0) poi…
http://acm.hdu.edu.cn/showproblem.php?pid=4036 一开始以为需要用斜抛,结果发现只需要用能量守恒定律?+与最大速度的坏土豆速度保持一致 #include <cstdio> #include <cstring> #include <cmath> #include <algorithm> using namespace std; const int maxn=1e3+3; int n,m; double w; doub…
http://acm.hdu.edu.cn/showproblem.php? pid=1124 題目好長好長,好可怕,看完腎都萎了,以後肯定活不長.我可不能死在這種小事上,小灰灰我勵志死在少女的超短裙下~~~哈哈,所以我就猥瑣的叫 旁邊的小師妹幫我翻譯了,我是不是非常禽獸,嘻嘻~~~ 題目大意呢,就是給一個數,要你求出它的階乘的得到的結果後面有幾個0. 解析: 一看就是簡單數論啦.跟數因子有關.最小素因子并且相乘能得到10的(就是後面有0的)就是2*5啦.因為一個數的階乘2的因子明顯比5的因子要…