已经是水到一定程度了QAQ- Code: #include<cstdio> #include<algorithm> #include<cstring> using namespace std; const int maxn = 105; int tp[maxn], idx[maxn], n,m, spare[maxn], cnt; bool cmp(int i,int j) { return i > j;} inline bool check(int val) {…

CF链接  http://codeforces.com/contest/1011/problem/A Natasha is going to fly to Mars. She needs to build a rocket, which consists of several stages in some order. Each of the stages is defined by a lowercase Latin letter. This way, the rocket can be de…

第一次作交互题,有点不习惯. 由于序列是循环的,我们可以将一半的机会用于判断当前是否是在说谎,另一半的机会用于二分的判断. 对于判断是否实在说谎,用1判断即可.因为不可能有比1还小的数. 本题虽然非常水,却十分有趣. Code: #include<cstring> #include<algorithm> #include<cstdio> #include<iostream> using namespace std; const int maxn = 100;…

A: Stages 题意: 给你n个字符, 现在需要从中选取m个字符,每个字符的花费为在字母表的第几位,并且如果选了某个字符, 那么下一个选择的字符必须要在字母表的2位之后, 假如选了e 那么 不能选 a-f 可以选择 g-z, 现在求能满足条件的最小花费. 题解: 直接模拟. 代码: #include<bits/stdc++.h> using namespace std; #define Fopen freopen("_in.txt","r",stdi…

http://codeforces.com/contest/1011/problem/C 题目 这是一道大水题! 仅以此题解作为我这个蒟蒻掉分的见证 #include<iostream> #include<cstdio> #include <cctype> #include<algorithm> #include<cstring> #include<cmath> #include<string> #include<c…

Codeforces Round #499 (Div. 2) https://codeforces.com/contest/1011 A #include <bits/stdc++.h> using namespace std; ]; string s; int main(){ ; sort(a,a+n); ,p=-;i<n&&j<k;i++){ <a[i])r+=a[i],j++,p=a[i]; } cout<<(j==k?r:-); } B #…

Description Natasha is planning an expedition to Mars for nn people. One of the important tasks is to provide food for each participant. The warehouse has m daily food packages. Each package has some food type aiai. Each participant must eat exactly…

Natasha is planning an expedition to Mars for nn people. One of the important tasks is to provide food for each participant. The warehouse has mm daily food packages. Each package has some food type aiai . Each participant must eat exactly one food p…

Codeforces Round #499 (Div. 1) 这场本来想和同学一起打\(\rm virtual\ contest\)的,结果有事耽搁了,之后又陆陆续续写了些,就综合起来发一篇题解. B.Rocket 极其简单的一道交互题,有些位置会说反的,那么就选一个数来询问直接选出所有的这样的位置 显然,选择\(\rm 1\)和\(\rm m\)都可以,选择完之后直接二分就行了 代码: #include<cstdio> #include<iostream> #include<…

Codeforces Round #499 (Div. 1) https://codeforces.com/contest/1010 为啥我\(\rm Div.1\)能\(A4\)题还是\(\rm specialist....\) A. Fly 二分答案,送分题. #include<bits/stdc++.h> using namespace std; void read(int &x) { x=0;int f=1;char ch=getchar(); for(;!isdigit(ch…