POJ 3256 DFS水题】的更多相关文章

枚举点 每次都搜一遍 //By SiriusRen #include <cstdio> #include <cstring> #include <algorithm> using namespace std; #define N 20005 int ans,k,n,m,first[N],next[N],v[N],tot,xx,yy,mark[N],vis[1005]; void add(int x,int y){ v[tot]=y,next[tot]=first[x],…
以下是poj百道水题,新手可以考虑从这里刷起 搜索1002 Fire Net1004 Anagrams by Stack1005 Jugs1008 Gnome Tetravex1091 Knight Moves1101 Gamblers1204 Additive equations 1221 Risk1230 Legendary Pokemon1249 Pushing Boxes 1364 Machine Schedule1368 BOAT1406 Jungle Roads1411 Annive…
题目描述: Description Given a specified total t and a list of n integers, find all distinct sums using numbers from the list that add up to t. For example, if t = 4, n = 6, and the list is [4, 3, 2, 2, 1, 1], then there are four different sums that equal…
http://wikioi.com/problem/1229/ 赤裸裸的水题啊. 一开始我认为不用用完全部的牌,以为爆搜会tle.. 可是我想多了. 将所有状态全部求出,排序后暴力判断即可. (水题有点严重啊) #include <cstdio> #include <algorithm> using namespace std; int n, m; int h[440000], cnt, a[12]; bool vis[12]; void dfs(int x, int sum, i…
题目传送门 /* 题意:一个圈,每个点有怪兽,每一次射击能消灭它左右和自己,剩余的每只怪兽攻击 搜索水题:sum记录剩余的攻击总和,tot记录承受的伤害,当伤害超过ans时,结束,算是剪枝吧 回溯写挫了,程序死循环,跑不出来.等回溯原理搞清楚了,下次自己重写一遍:) */ #include <cstdio> #include <algorithm> #include <cstring> #include <cmath> #include <iostre…
题意:找到一段数字里最大值和最小值的差 水题 #include<cstdio> #include<iostream> #include<algorithm> #include<cstring> #include<cmath> #include<queue> using namespace std; ; const int INF=0x3f3f3f3f; int n,m,t; ; ],dpMIN[MAXN][]; int mm[MAXN…
一.Description As part of an arithmetic competency program, your students will be given randomly generated lists of from 2 to 15 unique positive integers and asked to determine how many items in each list are twice some other item in the same list. Yo…
DFS的核心就是从一种状态出发,转向任意的一个可行状态,直到达到结束条件为止.(个人理解) 下面全是洛谷题,毕竟能找到测试点数据的OJ我就找到这一个....在其他OJ上直接各种玄学问题... P1596 [USACO10OCT] 湖计数Lake Counting DFS入门题,求连通块的. #include<iostream> #include<algorithm> using namespace std; ]={-,-,-, , , ,,};//方向 ]={-, , ,-, ,-…
Description There is a rectangular room, covered with square tiles. Each tile is colored either red or black. A man is standing on a black tile. From a tile, he can move to one of four adjacent tiles. But he can't move on red tiles, he can move only…
http://poj.org/problem?id=1562                                                                                                    Oil Deposits Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 12595   Accepted: 6868 Description The GeoSurv…