Given a list of positive integers, the adjacent integers will perform the float division. For example, [2,3,4] -> 2 / 3 / 4. However, you can add any number of parenthesis at any position to change the priority of operations. You should find out how…

题目: Given a list of positive integers, the adjacent integers will perform the float division. For example, [2,3,4] -> 2 / 3 / 4. However, you can add any number of parenthesis at any position to change the priority of operations. You should find out…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/optimal-division/description/ 题目描述 Given a list of positive integers, the adjacent integers will perform the float division. For example,…

题目如下: 解题思路:这是数学上的一个定理.对于x1/x2/x3/..../xN的序列,加括号可以得到的最大值是x1/(x2/x3/..../xN). 代码如下: class Solution(object): def optimalDivision(self, nums): """ :type nums: List[int] :rtype: str """ if len(nums) == 1: return str(nums[0]) elif…

Given a list of positive integers, the adjacent integers will perform the float division. For example, [2,3,4] -> 2 / 3 / 4. However, you can add any number of parenthesis at any position to change the priority of operations. You should find out how…

Given a list of positive integers, the adjacent integers will perform the float division. For example, [2,3,4] -> 2 / 3 / 4. However, you can add any number of parenthesis at any position to change the priority of operations. You should find out how…

原题链接在这里:https://leetcode.com/problems/optimal-division/description/ 题目: Given a list of positive integers, the adjacent integers will perform the float division. For example, [2,3,4] -> 2 / 3 / 4. However, you can add any number of parenthesis at any…

A group of friends went on holiday and sometimes lent each other money. For example, Alice paid for Bill's lunch for $10. Then later Chris gave Alice $5 for a taxi ride. We can model each transaction as a tuple (x, y, z) which means person x gave per…

突然很想刷刷题,LeetCode是一个不错的选择,忽略了输入输出,更好的突出了算法,省去了不少时间. dalao们发现了任何错误,或是代码无法通过,或是有更好的解法,或是有任何疑问和建议的话,可以在对应的随笔下面评论区留言,我会及时处理,在此谢过了. 过程或许会很漫长,也很痛苦,慢慢来吧. 编号 题名 过题率 难度 1 Two Sum 0.376 Easy 2 Add Two Numbers 0.285 Medium 3 Longest Substring Without Repeating C…

1. 551. Student Attendance Record I 2. 552. Student Attendance Record II hihocode原题,https://hihocoder.com/contest/offers10/problems 直接粘贴代码. 其实这个第二题的问题挺多的,这里还是写一下分析过程. 我刚开始做的时候,考虑也是计数dp,一维记录a的个数,一维记录末尾l的个数,然后考虑转移,后来好像是因为转移情况复杂,简化为不考虑a的个数,因为a的个数只有1个,所以…