problem 1170. Compare Strings by Frequency of the Smallest Character 参考 1. Leetcode_easy_1170. Compare Strings by Frequency of the Smallest Character; 完…
题目如下: Let's define a function f(s) over a non-empty string s, which calculates the frequency of the smallest character in s. For example, if s = "dcce" then f(s) = 2 because the smallest character is "c"and its frequency is 2. Now, giv…
Let's define a function f(s) over a non-empty string s, which calculates the frequency of the smallest character in s. For example, if s = "dcce" then f(s) = 2 because the smallest character is "c" and its frequency is 2. Now, given st…
1.题目描述 Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1. Examples: s = "leetcode" return 0. s = "loveleetcode", return 2. Note: You may assume the string contain only…
版权声明: 本文为博主Bravo Yeung(知乎UserName同名)的原创文章,欲转载请先私信获博主允许,转载时请附上网址 http://blog.csdn.net/lzuacm. Leetcode 557. 反转字符串中的单词 III - 题解 Leetcode 557. Reverse Words in a String III 在线提交: https://leetcode.com/problems/reverse-words-in-a-string-iii/description/ 题…
移除重复字符很简单,这里是最笨,也是最简单的一种.问题关键是理解排序的意义: # coding=utf-8 #learning at jeapedu in 2013/10/26 #移除给定字符串中重复字符,参数s是字符串 def removeDuplicate(s): s = list(s) s.sort() #对给定字符串排序,不排序可能移除不完整 for i in s: while s.count(i) > 1: s.remove(i) s = "".join(s) #把列表…
