Description Some positive integers can be represented by a sum of one or more consecutive prime numbers. How many such representations does a given positive integer have? For example, the integer 53 has two representations 5 + 7 + 11 + 13 + 17 and 53…

Description: Count the number of prime numbers less than a non-negative number, n click to show more hints. References: How Many Primes Are There? Sieve of Eratosthenes Credits:Special thanks to @mithmatt for adding this problem and creating all test…

题目描述 将中缀表达式(infix expression)转换为后缀表达式(postfix expression).假设中缀表达式中的操作数均以单个英文字母表示,且其中只包含左括号'(',右括号‘)’和双目算术操作符+,-,*,/. 输入格式 第一行是测试样例个数n.以下n行,每行是表示中缀表达式的一个字符串(其中只包含操作数和操作符和左右括号,不包含任何其他字符),长度不超过100个字符. 输出格式 为每一个测试样例单独一行输出对应后缀表达式字符串(其中只包含操作数和操作符,不包含任何其他字符…

Description 你有一些小球,从左到右依次编号为1,2,3,...,n. 你可以执行两种指令(1或者2).其中, 1 X Y表示把小球X移动到小球Y的左边, 2 X Y表示把小球X移动到小球Y右边. 指令保证合法,即X不等于Y. 例如,初始状态1,2,3,4,5,6的小球执行1 1 4后,小球1被移动到小球4的左边,即2,3,1,4,5,6.如果再执行2 3 5,结点3将会移到5的右边,即2,1,4,5,3,6. Input 第一行为一个整数t(0<t<10),表示测试用例个数.每个测…

The sum of the primes below 10 is 2 + 3 + 5 + 7 = 17. Find the sum of all the primes below two million. 译文: 10以下的素数之和为17,求出2000000以下的素数之和. ======================= 第一次code: import java.util.Scanner; public class Main { public static void main(String[]…

题目大家都非常熟悉,求小于n的所有素数的个数. 自己写的python 代码老是通不过时间门槛,无奈去看了看大家写的code.下面是我看到的投票最高的code: class Solution: # @param {integer} n # @return {integer} def countPrimes(self, n): if n < 3: return 0 primes = [True] * n primes[0] = primes[1] = False for i in range(2,…

examination questions Description: Count the number of prime numbers less than a non-negative number, n References: How Many Primes Are There? Sieve of Eratosthenes Please use the following function to solve the problem: int countPrimes(int n){ } 解题代…

Count Primes Description: Count the number of prime numbers less than a non-negative number, n click to show more hints. References: How Many Primes Are There? Sieve of Eratosthenes Credits: Special thanks to @mithmatt for adding this problem and cre…

Count the number of prime numbers less than a non-negative number, n public int countPrimes(int n) { ArrayList<Integer> primes = new ArrayList<Integer>(); ) , n - ); primes.add(); primes.add(); ; i <= n; i++) { boolean isPrime = true; for (…

http://acm.hdu.edu.cn/showproblem.php?pid=4715 Difference Between Primes Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Problem Description All you know Goldbach conjecture.That is to say, Every even integer great…