HDU 3923 Invoker(polya定理+逆元)】的更多相关文章

Invoker Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 122768/62768K (Java/Other) Total Submission(s) : 1   Accepted Submission(s) : 0 Font: Times New Roman | Verdana | Georgia Font Size: ← → Problem Description On of Vance's favourite hero i…
Invoker Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 122768/62768 K (Java/Others)Total Submission(s): 907    Accepted Submission(s): 364 Problem Description On of Vance's favourite hero is Invoker, Kael. As many people knows Kael can contr…
参考了http://blog.csdn.net/ACM_cxlove?viewmode=contents           by---cxlove 的模板 对于每一种染色,都有一个等价群,例如旋转,翻转等.我们将每一种变换转换成一个置换群,通过置换群得到的都是等价的染色方案 最终我们要求的是非等价的染色方案数. 在Burnside定理中给出,在每一种置换群也就是等价群中的数量和除以置换群的数量,即非等价的着色数等于在置换群中的置换作用下保持不变的着色平均数. 我们以POJ 2409 Let i…
链接:http://poj.org/problem?id=1286 http://poj.org/problem?id=2409 #include <cstdio> #include <iostream> #include <cstring> #include <cmath> #include <algorithm> using namespace std; typedef long long LL; LL P_M( LL a, LL b ) {…
暑训第一天,专题为组合数学与概率期望. 最近一个月都没有学习新的知识,上午听聚聚讲课头脑都是一片空白.加上长期没刷题,下午做练习题毫无感觉.到晚上总算理清了蓝书上的一些概念,跟着榜单做题.最后唯独剩下C题令人抓狂,照着蓝书代码敲上去一直WA,直到今天逐行对照网上博客修改才完全弄明白. C题相当于蓝书P146的例题18项链与手镯,即求有m种颜色的n颗珠子组成的手镯的个数,也就是等价类的计数问题,直接使用Polya定理. Input The first line contains a single…
Invoker Problem Description On of Vance's favourite hero is Invoker, Kael. As many people knows Kael can control the elements and combine them to invoke a powerful skill. Vance like Kael very much so he changes the map to make Kael more powerful.  In…
完全是套用polya模版…… ;}…
题目地址:http://acm.hdu.edu.cn/showproblem.php?pid=4633 典型的Polya定理: 思路:根据Burnside引理,等价类个数等于所有的置换群中的不动点的个数的平均值,根据Polya定理,不动点的个数等于Km(f),m(f)为置换f的循环节数,因此一次枚举魔方的24中置换,人肉数循环节数即可,注意细节,别数错了. 1.静止不动,(顶点8个循环,边12个循环,面54个循环) 2.通过两个对立的顶点,分别旋转120,240,有4组顶点,(点4个循环,边4个…
Necklace of Beads Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 630    Accepted Submission(s): 232 Problem Description Beads of red, blue or green colors are connected together into a circular…
DIY CubeTime Limit: 2000/2000 MS (Java/Others)    Memory Limit: 65535/32768 K (Java/Others)Total Submission(s): 207    Accepted Submission(s): 111 Problem Description Mr. D is interesting in combinatorial enumeration. Now he want to find out the numb…