题目链接:http://codeforces.com/problemset/problem/589/F A gourmet came into the banquet hall, where the cooks suggested n dishes for guests. The gourmet knows the schedule: when each of the dishes will be served. For i-th of the dishes he knows two integ…
F. Gourmet and Banquet time limit per test 2 seconds memory limit per test 512 megabytes input standard input output standard output A gourmet came into the banquet hall, where the cooks suggested n dishes for guests. The gourmet knows the schedule:…
解题的思路很巧,为了让每个数之间都留出对应的上升空间,使a[i]=a[i]-i,然后再求LIS 另外二分求LIS是比较快的 #include<bits/stdc++.h> #define maxn 1000005 #define ll long long using namespace std; int len,n,a[maxn],lis[maxn]; int main(){ int t; scanf("%d",&t); ;tt<=t;tt++){ scanf…
二分求幂 int getMi(int a,int b) { ; ) { //当二进制位k位为1时,需要累乘a的2^k次方,然后用ans保存 == ) { ans *= a; } a *= a; b /= ; } return ans; } 快速幂取模运算 公式: 最终版算法: int PowerMod(int a, int b, int c) { ; a = a % c; ) { = = )ans = (ans * a) % c; b = b/; a = (a * a) % c; } retur…
