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这道题是并差集的简单应用 #include <cstdio> #include <cstring> #include <algorithm> #define maxn 100010 using namespace std; int x[maxn],y[maxn],flag[maxn],f[maxn],t[maxn]; bool vis[maxn]; inline int find(int x) { if(x==f[x]) return x; return f[x]=fi…
1671 并查集 对于询问删除边之后的连通块 可以倒着加边 最后再倒序输出 #include <iostream> #include<cstdio> #include<cstring> #include<algorithm> #include<stdlib.h> using namespace std; #define N 100010 int p[N],father[N],a,b,f[N]; int pp[N]; struct node { i…
Anansi's Cobweb Time limit: 1.0 secondMemory limit: 64 MB Usatiy-Polosatiy XIII decided to destroy Anansi's home — his cobweb. The cobweb consists of Nnodes, some of which are connected by threads. Let us say that two nodes belong to the same piece i…
题目链接 题意:求给定的字符串的最长回文子串 分析:做法是构造一个新的字符串是原字符串+反转后的原字符串(这样方便求两边回文的后缀的最长前缀),即newS = S + '$' + revS,枚举回文串中心位置,RMQ询问LCP = min (height[rank[l]+1] to height[rank[r]]),注意的是RMQ传入参数最好是后缀的位置,因为它们在树上的顺序未知,且左边还要+1. #include <cstdio> #include <algorithm> #in…
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