http://poj.org/problem?id=3422 (题目链接) 题意 N*N的方格,每个格子中有一个数,寻找从(1,1)走到(N,N)的K条路径,使得取到的数的和最大. Solution 同[codevs1277] 方格取数 代码 // poj3422 #include<algorithm> #include<iostream> #include<cstring> #include<cstdlib> #include<cstdio>…

http://poj.org/problem?id=3422 题目大意: 从左上角走到右下角,中途取数(数>=0),然后该点的数变为0,求走k的总价值和最大值. —————————————————————————————— 最大值?但是我们只会最小费用流啊…… 但是数是>=0的啊,所以…… 我们拆点,中间连一条容量为1费用为当前值负值的边,再连一条容量为k-1费用0的边. 这样就一定会先走前一条边啦! 然后向下向右连一条容量为k费用0的边. 源点到左上角连一条容量为k-1费用0的边. 右下角到…

POJ3422 Kaka's Matrix Travels Description On an N × N chessboard with a non-negative number in each grid, Kaka starts his matrix travels with SUM = 0. For each travel, Kaka moves one rook from the left-upper grid to the right-bottom one, taking care…

Kaka's Matrix Travels Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 9522   Accepted: 3875 Description On an N × N chessboard with a non-negative number in each grid, Kaka starts his matrix travels with SUM = 0. For each travel, Kaka mo…

/* poj3422 Kaka's Matrix Travels 不知道 k次 dp做为什么不对??? 看了大牛的代码,才知道还可以这样做! 开始没有理解将a 和 a‘ 之间建立怎样的两条边,导致程序一直陷入死循环,真心花了好长时间,快崩溃了.无语..... 题意:有个方阵,每个格子里都有一个非负数,从左上角走到右下角,每次走一步,只能往右或往下走,经过的数字拿走 每次都找可以拿到数字和最大的路径走,走k次,求最大和 这是 最大费用最大流 问题 每次spfa都找的是一条和最大的路径 s--到左上…

Kaka's Matrix Travels Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 9567   Accepted: 3888 Description On an N × N chessboard with a non-negative number in each grid, Kaka starts his matrix travels with SUM = 0. For each travel, Kaka mo…

Kaka's Matrix Travels Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 6792   Accepted: 2679 Description On an N × N chessboard with a non-negative number in each grid, Kaka starts his matrix travels with SUM = 0. For each travel, Kaka mo…

[题解]Sonya and Matrix Beauty [Codeforces1080E] 传送门:\(Sonya\) \(and\) \(Matrix\) \(Beauty\) \([CF1080E]\) [题目描述] \(Sonya\) 最近过了生日,她收到一个 \(n \times m\) 的字符矩阵. 我们称一个子矩阵是美丽的,当且仅当在重新排列这个子矩阵每一行的字符后,使得这个子矩阵的每一行每一列都是回文串. \(Sonya\) 想要知道这个矩阵中有几个子矩阵是美丽的. (给定一个 \…

描述 On an N × N chessboard with a non-negative number in each grid, Kaka starts his matrix travels with SUM = 0. For each travel, Kaka moves one rook from the left-upper grid to the right-bottom one, taking care that the rook moves only to the right o…

[论文标题]Sparse Probabilistic Matrix Factorization by Laplace Distribution for Collaborative Filtering     (24th-IJCAI ) (Proceedings of the Twenty-Fourth International Joint Conference on Artificial Intelligence (IJCAI 2015) ) [论文作者]Liping Jing, PengWa…