［抄题］: We define the Perfect Number is a positive integer that is equal to the sum of all its positive divisors except itself. Now, given an integer n, write a function that returns true when it is a perfect number and false when it is not. Example: I…

problem 507. Perfect Number solution: /* class Solution { public: bool checkPerfectNumber(int num) { int sum = 1; for(int i=2; i*i<=num; i++) { if(num%i==0) sum += i + (num/i == i) ? 0 : num/i; // } return (sum == num) && (num!=1); } }; */ clas…

We define the Perfect Number is a positive integer that is equal to the sum of all its positive divisors except itself. Now, given an integer n, write a function that returns true when it is a perfect number and false when it is not. Example: Input:…

We define the Perfect Number is a positive integer that is equal to the sum of all its positive divisors except itself. Now, given an integer n, write a function that returns true when it is a perfect number and false when it is not. Example: Input:…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/perfect-number/#/description 题目描述 We define the Perfect Number is a positive integer that is equal to the sum of all its positive divisors…

对于一个 正整数,如果它和除了它自身以外的所有正因子之和相等,我们称它为“完美数”.给定一个 正整数 n, 如果他是完美数,返回 True,否则返回 False示例:输入: 28输出: True解释: 28 = 1 + 2 + 4 + 7 + 14注意:输入的数字 n 不会超过 100,000,000. (1e8)详见:https://leetcode.com/problems/perfect-number/description/ C++: class Solution { public: b…

这是悦乐书的第249次更新,第262篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第116题(顺位题号是507).我们定义Perfect Number是一个正整数,它等于除了它自己之外的所有正除数之和.现在,给定一个整数n,编写一个函数,当它是一个完美数字时返回true,否则返回false.例如: 输入:28 输出:true 说明:28 = 1 + 2 + 4 + 7 + 14 注意:输入数字n不会超过100,000,000.(1E8) 本次解题使用的开发工具是ec…

We define the Perfect Number is a positive integer that is equal to the sum of all its positive divisors except itself. Now, given an integer n, write a function that returns true when it is a perfect number and false when it is not. Example: Input:…

We define the Perfect Number is a positive integer that is equal to the sum of all its positive divisors except itself. Now, given an integer n, write a function that returns true when it is a perfect number and false when it is not. Example: Input:…

原题链接在这里:https://leetcode.com/problems/perfect-number/#/description 题目: We define the Perfect Number is a positive integer that is equal to the sum of all its positive divisors except itself. Now, given an integer n, write a function that returns true…

B. Perfect Number time limit per test2 seconds memory limit per test256 megabytes Problem Description We consider a positive integer perfect, if and only if the sum of its digits is exactly 10. Given a positive integer k, your task is to find the k-t…

  B. Perfect Number   time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output We consider a positive integer perfect, if and only if the sum of its digits is exactly 10. Given a positive integer k…

题目传送门 B. Perfect Number time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output We consider a positive integer perfect, if and only if the sum of its digits is exactly 1010. Given a positive integ…

问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/3879 访问. 对于一个 正整数,如果它和除了它自身以外的所有正因子之和相等,我们称它为"完美数". 给定一个 正整数 n, 如果他是完美数,返回 True,否则返回 False 输入: 28 输出: True 解释: 28 = 1 + 2 + 4 + 7 + 14 注意:输入的数字 n 不会超过 100,000,000. (1e8) We define…

Problem description We consider a positive integer perfect, if and only if the sum of its digits is exactly 10. Given a positive integer k, your task is to find the k-th smallest perfect positive integer. Input A single line with a positive integer k…

[链接] 我是链接,点我呀:) [题意] 在这里输入题意 [题解] 直接暴力求出第k个perfect数字就好. 纯模拟. [代码] #include <bits/stdc++.h> #define double long double using namespace std; int n; int _judge(int x){ int num = 0; while (x){ num+=x%10; x/=10; } return num==10; } int main(){ #ifdef LOC…

 题目链接:https://nanti.jisuanke.com/t/38220 题目大意:这道题让我们判断给定数字是否为完美数字,并给来完美数字的定义,就是一个整数等于除其自身之外的所有的因子之和. 首先打表前三个,发现满足 n = 1+2^1 + 2^2 + 2^3 + 2^z + (n/(2^1))+(n/(2^2))+...+n/(2^z). 然后化简这个式子,就是n=2^z*(2^z-1).然后枚举z就可以了,看看有没有满足的. AC代码: #include<bits/stdc++.h…

题目链接:http://codeforces.com/problemset/problem/919/B AC代码: #include<cstdio> using namespace std; //对全局变量或者对于一个或多个函数来说是全局的变量的时候,要注意上次用完该变量后变量的值,看其是否需要进行初始化. int main() { int k, index = 1, stemp, s = 19; int arr[10005]; int sum = 0; while (scanf("…

Content 给定一个数字 \(k\),求出第 \(k\) 小的各数位和为 \(10\) 的数. 数据范围:\(1\leqslant k\leqslant 10000\). Solution 这题为什么不可以打表解决呢?我们可以直接枚举.判断,获得所有第 \(1\sim10000\) 个各数位和为 \(10\) 的数,然后就可以直接输出答案了. Code int k, f[10007], cur; int main() { while(f[0] < 10000) { int sum = 0,…

源代码地址:https://github.com/hopebo/hopelee 语言:C++ 301. Remove Invalid Parentheses Remove the minimum number of invalid parentheses in order to make the input string valid. Return all possible results. Note: The input string may contain letters other tha…

突然很想刷刷题,LeetCode是一个不错的选择,忽略了输入输出,更好的突出了算法,省去了不少时间. dalao们发现了任何错误,或是代码无法通过,或是有更好的解法,或是有任何疑问和建议的话,可以在对应的随笔下面评论区留言,我会及时处理,在此谢过了. 过程或许会很漫长,也很痛苦,慢慢来吧. 编号 题名 过题率 难度 1 Two Sum 0.376 Easy 2 Add Two Numbers 0.285 Medium 3 Longest Substring Without Repeating C…

1. 507. Perfect Number 显然小于2的都不满足(尤其是负数的情况),进一步,显然质数都不满足,所以小于4的数,直接return false. 然后依次暴力枚举判断到sqrt(n),注意n = t * t的时候,t只需要加一次.好像不写这个也不会出错,因为没有这样的数满足条件.我没验证,需要的验证一下. class Solution { public: bool checkPerfectNumber(int num) { ) ; ; int d = floor(sqrt(num…

All LeetCode Questions List(Part of Answers, still updating) 题目汇总及部分答案(持续更新中) Leetcode problems classified by company 题目按公司分类(Last updated: October 2, 2017) .   Top Interview Questions # Title Difficulty Acceptance 1 Two Sum Medium 17.70% 2 Add Two N…

终于将LeetCode的免费题刷完了,真是漫长的第一遍啊,估计很多题都忘的差不多了,这次开个题目汇总贴,并附上每道题目的解题连接,方便之后查阅吧~ 如果各位看官们,大神们发现了任何错误,或是代码无法通过OJ,或是有更好的解法,或是有任何疑问,意见和建议的话,请一定要在对应的帖子下面评论区留言告知博主啊(如果不方便注册博客园的话,可以下载下文提到的APP,在Feedback中给博主发邮件交流哈),同时也请大家踊跃地,大量地,盲目地提供各个题目的follow up一起讨论哈,多谢多谢,祝大家刷得愉快…

Paula and Tai are couple. There are many stories between them. The day Paula left by airplane, Tai send one message to telephone 2200284, then, everything is changing- (The story in "the snow queen"). After a long time, Tai tells Paula, the numb…

CCC加拿大高中生信息学奥赛 其余来源 CODEVS[3312]——CCC 1996 01 Deficient, Perfect, and Abundant ——http://codevs.cn/problem/3312/ POJ[1928]——Perfection——http://poj.org/problem?id=1528 CODEVS描述——中文题目 题目描述 Description 读入一个正整数n,判断整数是完数,亏数还是盈数. •如果它的约数的和等于它本身,那它便是一个完数(Per…

#include <pthread.h>#include <stdio.h>#include <sys/time.h>#include <string.h>#include <unistd.h>#define MAX 10 pthread_t thread[2];pthread_mutex_t mut;int number=0,i; void *thread1(){while(1){number=i;printf ("Thread1:…

We define the Perfect Number is a positive integer that is equal to the sum of all its positive divisors except itself. Now, given an integer n, write a function that returns true when it is a perfect number and false when it is not. Example: Input:…

问题 : Friends number 时间限制: 1 Sec  内存限制: 128 MB 题目描述 Paula and Tai are couple. There are many stories between them. The day Paula left by airplane, Tai send one message to telephone 2200284, then, everything is changing- (The story in "the snow queen&q…

Time limit  1000 ms Memory limit   131072 kB Paula and Tai are couple. There are many stories between them. The day Paula left by airplane, Tai send one message to telephone 2200284, then, everything is changing… (The story in “the snow queen”). Afte…