【LeetCode】23. Merge k Sorted Lists

【LeetCode】23. Merge k Sorted Lists 合并K个升序链表

作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 个人公众号:负雪明烛本文关键词:合并,链表,单链表,题解,leetcode, 力扣,Python, C++, Java 题目地址: https://leetcode.com/problems/merge-k-sorted-lists/description/ 题目描述: Merge k sorted linked lists and return it as one sorted li…

【LeetCode】23. Merge k Sorted Lists

合并k个已合并链表. 思路:先把链表两两合并,直到合并至只有一个链表 /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* mergeKLists(vector<ListNode*>& list…

【一天一道LeetCode】#23. Merge k Sorted Lists

一天一道LeetCode系列 (一)题目 Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. (二)解题合并K个已拍好序的链表.剑指上有合并两个已排好序的链表的算法,那么K个数,我们可以采用归并排序的思想,不过合并函数可能需要修改一下,换成合并两个已排好序的链表的方法.代码如下: /** * Definition for singly-linked…

【LeetCode】023. Merge k Sorted Lists

Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 题解: 归并思想. Solution 1 /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {…

[Leetcode][Python]23: Merge k Sorted Lists

# -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 23: Merge k Sorted Listshttps://oj.leetcode.com/problems/merge-k-sorted-lists/ Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. ===Comments…

【LeetCode】21. Merge Two Sorted Lists 合并两个有序链表

作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 个人公众号:负雪明烛本文关键词:合并,有序链表,递归,迭代,题解,leetcode, 力扣,Python, C++, Java 目录题目描述题目大意解题方法迭代 Python解法 C++解法 Java解法递归日期题目地址:https://leetcode.com/problems/merge-two-sorted-lists/ 题目描述 Merge two sorted…

【原创】leetCodeOj --- Merge k Sorted Lists 解题报告

题目地址: https://oj.leetcode.com/problems/merge-k-sorted-lists/ 题目内容: /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ Merge k sorted linked lists and return it a…

LeetCode LinkList 23. Merge k Sorted Lists

这两天一直也没有顾上记录一下自己做过的题目,回头看看,感觉忘的好快,今天做了一个hard,刚开始觉得挺难得,想了两种方法,一种是每次都从k个list中选取最小的一个,为空的直接跳过,再就是每次合并其中的两个list,直到最终合并完成,这就要用到地柜的方法,还有就是划分,感觉递归的思路比较清晰,就拿地柜的写了,使用递归的方法,这道题目就是以21. Merge Two Sorted Lists 为基础的. 阶梯思路就是,每次都从中间切割lists,直到切割完之后左侧或者右侧为,一个或者两个list…

【Lintcode】104.Merge k Sorted Lists

题目: Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. Example Given lists: [ 2->4->null, null, -1->null ], return -1->2->4->null. 题解: Solution 1 () class Solution { public: struct compare…

【LeetCode】21. Merge Two Sorted Lists

题目: Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 思路:比较每个列表的第一个元素. 合并小的添加到列表中. 最后,当其中一个是空的,只需将它附加到合并后的列表,因为它已经排序. /** * Definition for singly-linked list.…

【leetcode】 21. Merge Two Sorted Lists

题目描述: Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 解题分析: 再基础不过的题了,直接看代码吧^-^ 具体代码: /** * Definition for singly-linked list. * public class ListNode { * in…

【LeetCode】021. Merge Two Sorted Lists

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 题解: 简单的链表遍历,还可用递归做. Solution…

Python 解LeetCode：23. Merge k Sorted Lists

题目描述:把k个排序的链表组成的列表合并成一个排序的链表思路: 使用堆排序,遍历列表,把每个列表中链表的头指针的值和头指针本身作为一个元素放在堆中: 第一步中遍历完列表后,此时堆中最多会有n个元素,n是列表的长度: 当堆不为空,取出堆中的最小值,然后把该值的指针指向下一个元素,并入堆: 第3步可以确保堆永远是o(n)大小的: 堆为空返回头结点就可以了 # Definition for singly-linked list. # class ListNode(object): # def __i…

23. Merge k Sorted Lists - LeetCode

Question 23. Merge k Sorted Lists Solution 题目大意:合并链表数组(每个链表中的元素是有序的),要求合并后的链表也是有序的思路:遍历链表数组,每次取最小节点 Java实现: public ListNode mergeKLists(ListNode[] lists) { ListNode preHead = new ListNode(0); ListNode minNode = getMinNode(lists); ListNode tmpNode =…

21.Merge Two Sorted Lists 、23. Merge k Sorted Lists

21.Merge Two Sorted Lists 初始化一个指针作为开头,然后返回这个指针的next class Solution { public: ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) { ListNode* dummy = ); ListNode* p = dummy; while(l1 && l2){ if(l1->val <= l2->val){ p->next = l1; p = p-&…

刷题23. Merge k Sorted Lists

一.题目说明这个题目是23. Merge k Sorted Lists,归并k个有序列表生成一个列表.难度为Hard,实际上并不难,我一次提交就对了. 二.我的解答就是k路归并,思路很简单,实现也不难. #include<iostream> #include<vector> using namespace std; struct ListNode { int val; ListNode *next; ListNode(int x) : val(x), next(NULL) {}…

蜗牛慢慢爬 LeetCode 23. Merge k Sorted Lists [Difficulty: Hard]

题目 Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 翻译合并k个有序的链表 Hints Related Topics: LinkedList, Divide and Conquer, Heap Solution1:Divide and Conquer 参考归并排序-维基百科思路:分治,先分成两个子任务,然后递归子任务,最后回溯回来..这里就…

[LeetCode] 23. Merge k Sorted Lists 合并k个有序链表

Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. Example: Input: [ 1->4->5, 1->3->4, 2->6 ] Output: 1->1->2->3->4->4->5->6 这道题让我们合并k个有序链表,最终合并出来的结果也必须是有序的,之前做过一道 M…

[leetcode 23]Merge k Sorted Lists

1 题目 Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 2 思路当时看到这个题目就想到的是归并排序.好吧,但是,具体代码写不出来.题目给的是数组:public ListNode mergeKLists(ListNode[] lists),我就想,怎么归并排序,然后返回一个已经排好的,再进行递归.想破脑袋没想出来. 原来,可以赋值给一个Array…

[LeetCode] 23. Merge k Sorted Lists ☆☆☆☆☆

转载:https://leetcode.windliang.cc/leetCode-23-Merge-k-Sorted-Lists.html 描述 Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. Example: Input:[ 1->4->5, 1->3->4, 2->6]Output: 1->1->2->3…

LeetCode 23 Merge k Sorted Lists（合并k个有序链表）

题目链接: https://leetcode.com/problems/merge-k-sorted-lists/?tab=Description Problem: 给出k个有序的list, 将其进行合并得到一个有序的list 对于给出的ListNode[] lists ,可以进行两两合并.divide and conquer 将list分为前后两部分,对前半部分再次进行分半操作,对后半部分进行分半操作,然后将其进行合并操作. 合并操作也就是对两个list进行合并合并操作可以采用递归算法…

Java [leetcode 23]Merge k Sorted Lists

题目描述: Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 解题思路: 分治方法.将K个List不断地分解为前半部分和后半部分.分别进行两个List的合并.最后将合并的结果合并起来. 代码如下: /** * Definition for singly-linked list. * public class ListNode { * int val;…

[leetcode]23. Merge k Sorted Lists归并k个有序链表

Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. Input: [ 1->4->5, 1->3->4, 2->6 ] Output: 1->1->2->3->4->4->5->6 题意: 归并k个有序链表. 思路: 用一个最小堆minHeap,将所有链表的头结点放入新建一个linkedl…

[LeetCode] 23. Merge k Sorted Lists ☆☆

Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 解法1: 采用递归的方法,不管合并几个,归根到底还是需要两两合并. 首先想到的是前两个先合并,然后再跟第三个合并,然后第四个....但是这种做法效率不高. 换个思路,采用分治法,对数量超过2的任务进行拆分,直到最后只有一个或两个链表再进行合并.代码如下: /** * Definition for si…

[LeetCode]23. Merge k Sorted Lists合并K个排序链表

Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. Example: Input: [ 1->4->5, 1->3->4, 2->6 ] Output: 1->1->2->3->4->4->5->6 要合并K个排好序的链表,我用的方法是用一个优先队列每次存K个元素在队列中,根据优…

leetcode 23. Merge k Sorted Lists(堆||分治法)

Merge k sorted linked lists and return it as one sorted list. 题意:把k个已经排好序的链表整合到一个链表中,并且这个链表是排了序的. 题解:这是一道经典好题,值得仔细一说. 有两种方法,假设每个链表的平均长度是n,那么这两种方法的时间复杂度都是O(nklogk). 方法一: 基本思路是:把k个链表开头的值排个序,每次取最小的一个值放到答案链表中,这次取完之后更新这个值为它后面的一个值.接着这么取一直到全部取完.那么每次更新之后怎么对当…

23. Merge k Sorted Lists

Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. ======= 合并k个链表形成一个已排序链表思路: 如何合并两个有序链表?经典merge算法: ListNode *mergeList(ListNode *head1,ListNode *head2){ ListNode dummy(-); ListNode *h = &dummy; while(…

23. Merge k Sorted Lists (JAVA)

Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. Example: Input: [ 1->4->5, 1->3->4, 2->6 ] Output: 1->1->2->3->4->4->5->6 /** * Definition for singly-linked lis…

23. Merge K Sorted Lists (Java, 归并排序的思路)

题目:Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 解析:合并k个已经有序的单链表,使其最终成为一个有序的单链表.原理就是归并排序,递归运算.基本算法recusion 与 merge 编码: public ListNode mergeKLists(ListNode[] lists) { if(lists == null || lists.leng…

23.Merge k Sorted Lists (Array, Queue; Sort)

Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 思路I: 选择排序每次都比较各个list的头指针所指的val,取最小的那个.时间复杂度O(n*k) class Solution { public: ListNode *mergeKLists(vector &lists) { if(lists.empty()) return NULL; ListN…

【【LeetCode】23. Merge k Sorted Lists】的更多相关文章