Remove Duplicates from Sorted List : Given a sorted linked list, delete all duplicates such that each element appear only once. For example,Given 1->1->2, return 1->2.Given 1->1->2->3->3, return 1->2->3. public ListNode deleteDu…

Given a sorted linked list, delete all duplicates such that each element appear only once. For example,Given 1->1->2, return 1->2.Given 1->1->2->3->3, return 1->2->3. 如题目所诉,去除递增链表中重复值的节点. 刚开始思路如下: 设置一个指针用于遍历全部节点 让每个节点和其next节点值比较…

给定一个排序链表,删除所有重复的元素使得每个元素只留下一个.案例:给定 1->1->2,返回 1->2给定 1->1->2->3->3,返回 1->2->3详见:https://leetcode.com/problems/remove-duplicates-from-sorted-list/description/ Java实现: 递归实现: /** * Definition for singly-linked list. * public class…

Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this in place with constant memory. For example,Given input array A = […

Given a sorted array nums, remove the duplicates in-place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.…

Given a sorted linked list, delete all duplicates such that each element appear only once. Example 1: Input: 1->1->2 Output: 1->2 Example 2: Input: 1->1->2->3->3 Output: 1->2->3 题意: 有序链表去重 思路: 代码: class Solution { public ListNod…

Given a sorted linked list, delete all duplicates such that each element appear only once. For example,Given 1->1->2, return 1->2.Given 1->1->2->3->3, return 1->2->3. 设置2个指针,cur 和next. 当cur的值与next的值相等时,cur.next= next.next   更新ne…

Given a sorted linked list, delete all duplicates such that each element appear only once. For example,Given 1->1->2, return 1->2.Given 1->1->2->3->3, return 1->2->3. 思路:两个指针,一个指向当前节点cur,一个指向下一个节点nx,终止条件,也就是比较了len-1次. 比较若不等,则两指针…

Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list. For example,Given 1->2->3->3->4->4->5, return 1->2->5.Given 1->1->1->2->3, return 2->3.…

[LeetCode] Remove Duplicates from Sorted Array 有序数组中去除重复项 描述 Given a sorted array nums, remove the duplicates in-place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this…