hdu3999-The order of a Tree （二叉树的先序遍历）

【hdu3999-The order of a Tree （二叉树的先序遍历）】的更多相关文章

hdu3999 The order of a Tree

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3999 题意:给一序列,按该序列插入二叉树,给出字典序最小的插入方法建相同的一棵树出来.即求二叉树的先序遍历. #include<bits/stdc++.h> using namespace std; struct node { int v; node *left,*right; }*root; node* build(node *root,int v) { if(root==NULL) { roo…

[LeetCode] Binary Tree Postorder Traversal 二叉树的后序遍历

Given a binary tree, return the postorder traversal of its nodes' values. For example: Given binary tree {1,#,2,3}, 1 \ 2 / 3 return [3,2,1]. Note: Recursive solution is trivial, could you do it iteratively? 经典题目,求二叉树的后序遍历的非递归方法,跟前序,中序,层序一样都需要用到栈,后续的…

[LeetCode] 145. Binary Tree Postorder Traversal 二叉树的后序遍历

Given a binary tree, return the postorder traversal of its nodes' values. For example: Given binary tree {1,#,2,3}, 1 \ 2 / 3 return [3,2,1]. Note: Recursive solution is trivial, could you do it iteratively? 经典题目,求二叉树的后序遍历的非递归方法,跟前序,中序,层序一样都需要用到栈,后序的…

[LeetCode] Binary Tree Inorder Traversal 二叉树的中序遍历

Given a binary tree, return the inorder traversal of its nodes' values. For example:Given binary tree {1,#,2,3}, 1 \ 2 / 3 return [1,3,2]. Note: Recursive solution is trivial, could you do it iteratively? confused what "{1,#,2,3}" means? > re…

lintcode：Binary Tree Postorder Traversal 二叉树的后序遍历

题目: 二叉树的后序遍历给出一棵二叉树,返回其节点值的后序遍历. 样例给出一棵二叉树 {1,#,2,3}, 1 \ 2 / 3 返回 [3,2,1] 挑战你能使用非递归实现么? 解题: 递归程序好简单 Java程序: /** * Definition of TreeNode: * public class TreeNode { * public int val; * public TreeNode left, right; * public TreeNode(int val) { * th…

LeetCode 94：二叉树的中序遍历 Binary Tree Inorder Traversal

题目: 给定一个二叉树,返回它的中序遍历. Given a binary tree, return the inorder traversal of its nodes' values. 示例: 输入: [1,null,2,3] 1 \ 2 / 3 输出: [1,3,2] 进阶: 递归算法很简单,你可以通过迭代算法完成吗? Follow up: Recursive solution is trivial, could you do it iteratively? 解题思路: 百度百科:二叉树的…

[LeetCode] 144. Binary Tree Preorder Traversal 二叉树的先序遍历

Given a binary tree, return the preorder traversal of its nodes' values. For example:Given binary tree {1,#,2,3}, 1 \ 2 / 3 return [1,2,3]. Note: Recursive solution is trivial, could you do it iteratively? 树的遍历,最常见的有先序遍历,中序遍历,后序遍历和层序遍历,它们用递归实现起来都非常的简…