题目大意: 给你一些子网,求它们在整个网段的补集. 思路: 将子网转换成二进制建一棵Trie,直接DFS搜到没有了就记下来输出.注意:所给的子网会有交集,若搜到结尾就不向下搜了. 代码: #include<cstdio> #include<cstring> #include<iostream> #include<algorithm> #define M 40000 using namespace std; ],flag[M<<],trie[M&l…

题目在这里>_< 发现这场比赛在网上没有完整的题解,甚至连题目代码都没人贴出来(大概是因为题目太水了吧...).所以宝宝就来写个题解,也就当作成长记录了233333 A. Window 题意很简单,给出n组x,y,求x*y的值 #include <cstdio> #include <algorithm> using namespace std; int main() { int n; long long x,y; scanf("%d",&n)…

[题目链接] A - Who Is The Winner 模拟. #include <bits/stdc++.h> using namespace std; int T; int n; struct X { string name; int num; int ti; }s[10010]; bool cmp(X&a,X&b){ if(a.num != b.num) return a.num > b.num; return a.ti < b.ti; } int main…

[题目链接] A - Watching TV 模拟.统计一下哪个数字最多即可. #include <bits/stdc++.h> using namespace std; const int maxn = 1e5 + 10; int T, n; char s[maxn]; int a[maxn]; int main() { scanf("%d", &T); while(T --) { scanf("%d", &n); memset(a,…

题目链接:给你n(n<=3e4)个路由地址(注意有子网掩码现象), 路由地址:128.0.0.0/1的形式 要求你输出一个路由集合,其是给定的路由集合的补集,且个数越少越好 #include <cstdio> #include <iostream> #include <algorithm> #include <cstring> #include <iostream> #include <cmath> #include <s…

Game Rooms Time Limit: 4000/4000MS (Java/Others)     Memory Limit: 65535/65535KB (Java/Others) Submit Status Your company has just constructed a new skyscraper, but you just noticed a terrible problem: there is only space to put one game room on each…

layout: post title: 2018-2019 ACM-ICPC Nordic Collegiate Programming Contest (NCPC 2018) author: "luowentaoaa" catalog: true tags: mathjax: true - codeforces 传送门 付队! B.Baby Bites (签到模拟) 按照题意模拟就行了 int a[maxn]; string s; int main() { std::ios::syn…

layout: post title: 2018 German Collegiate Programming Contest (GCPC 18) author: "luowentaoaa" catalog: true tags: mathjax: true - codeforces 传送门 付队博客 C.Coolest Ski Route (记忆化搜索) 题意 给出一个有向图,求出一个权值最长的链, 题解 暴力dfs会超时,所以直接储存每个起点能走到的最远距离 #include<…

2017-2018 ACM-ICPC Nordic Collegiate Programming Contest (NCPC 2017) 今日份的训练,题目难度4颗星,心态被打崩了,会的算法太少了,知道要用什么写,但是写不出来啊(抱头痛哭)和猪队友一共写出来3道题,本来I题应该可以写出来的,有向图求最小环输出路径就可以,But,没有板子啊!!!(｡•́︿•̀｡) 赛后补题,补一下I(单独写),D题和E题表示读不懂题,不知道要干嘛,D题是bfs+位运算 ,E题是bfs+优先队列,题意都读不懂,题解…

Secrete Master Plan Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others)Total Submission(s): 429    Accepted Submission(s): 244 Problem Description Master Mind KongMing gave Fei Zhang a secrete master plan stashed in a…