Given an array of numbers nums, in which exactly two elements appear only once and all the other elements appear exactly twice. Find the two elements that appear only once.For example:Given nums = [1, 2, 1, 3, 2, 5], return [3, 5].Note:1.The order of…
给定一个整数数组 nums,其中恰好有两个元素只出现一次,其他所有元素均出现两次. 找出只出现一次的那两个元素.示例:给定 nums = [1, 2, 1, 3, 2, 5], 返回 [3, 5].注意:    结果的顺序并不重要,对于上面的例子 [5, 3] 也是正确答案.    你的算法应该具有线性复杂度,你能否仅使用恒定的空间复杂度来实现它?详见:https://leetcode.com/problems/single-number-iii/description/ Java实现: cla…
给定一个整型数组,除了一个元素只出现一次外,其余每个元素都出现了三次.求出那个只出现一次的数.注意:你的算法应该具有线性的时间复杂度.你能否不使用额外的内存来实现?详见:https://leetcode.com/problems/single-number-ii/description/ Java实现: 建立一个32位的数组,来统计每一位上1出现的个数,如果某一位上为1的话,那么如果该整数出现了三次,对3去余为0,把每个数的对应位都加起来对3取余,最终剩下来的那个数就是单独的数字. 参考:htt…
Given an array of integers, every element appears three times except for one, which appears exactly once. Find that single one.Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? class Solut…
136. Single Number 除了一个数字,其他数字都出现了两遍. 用亦或解决,亦或的特点:1.相同的数结果为0,不同的数结果为1 2.与自己亦或为0,与0亦或为原来的数 class Solution { public: int singleNumber(vector<int>& nums) { if(nums.empty()) ; ; ;i < nums.size();i++) res ^= nums[i]; return res; } }; 137. Single N…
leetcode 136. Single Number Given an array of integers, every element appears twice except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 解题思路: 如果以线性复杂度和…
LeetCode 260. Single Number III(只出现一次的数字 III)…
题目:在一个数组中,除了两个数外,其余数都是两两成对出现,找出这两个数,要求时间复杂度O(n),空间复杂度O(1) 分析:这道题考察位操作:异或(^),按位与(&),移位操作(>>, <<)等,Java代码及注释如下: public static int[] findTwoSingleNum(int[] num) { int[] twoNums = new int[2]; int result = 0; for (int i = 0; i < num.length;…
Single Number III Given an array of numbers nums, in which exactly two elements appear only once and all the other elements appear exactly twice. Find the two elements that appear only once. Example: Input: [1,2,1,3,2,5] Output: [3,5] Note: The order…
一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Given an array of numbers nums, in which exactly two elements appear only once and all the other elements appear exactly twice. Find >the two elements that a…
传送门 Description Given an array of numbers nums, in which exactly two elements appear only once and all the other elements appear exactly twice. Find the two elements that appear only once. For example: Given nums = [1, 2, 1, 3, 2, 5], return [3, 5].…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 异或 字典 日期 题目地址:https://leetcode.com/problems/single-number-iii/description/ 题目描述 Given an array of numbers nums, in which exactly two elements appear only once and all the other…
给定一个整数数组,除了某个元素外其余元素均出现两次.请找出这个只出现一次的元素.备注:你的算法应该是一个线性时间复杂度. 你可以不用额外空间来实现它吗? 详见:https://leetcode.com/problems/single-number/description/ Java实现: class Solution { public int singleNumber(int[] nums) { int n=nums.length; if(n==0||nums==null){ return In…
Given an array of numbers nums, in which exactly two elements appear only once and all the other elements appear exactly twice. Find the two elements that appear only once. Example: Input: [1,2,1,3,2,5] Output: [3,5] Note: The order of the result is…
题目描述: Given an array of numbers nums, in which exactly two elements appear only once and all the other elements appear exactly twice. Find the two elements that appear only once. For example: Given nums = [1, 2, 1, 3, 2, 5], return [3, 5]. Note: The…
问题描述: https://leetcode.com/problems/single-number-iii/ 在一个数组里面,只有两个元素仅出现过1次,其余都出现过两次.找出出现仅一次的那两个(a, b). 要求常量空间,线性时间. 问题解决: 这题用到“神奇的位运算”. 1.因为除了特殊的两个元素,其余两两出现,那么就想到了XOR(异或). 2.从头到尾XOR之后,会得到a xor b 的结果.接下来我们试着把这两个元素分离开来. 3.我们在a xor b 中找到任意一位XOR[diff_po…
在一个数组中找出两个不同的仅出现一次的数(其他数字出现两次) 同样用亦或来解决(参考编程之美的1.5) 先去取出总亦或值 然后分类,在最后一位出现1的数位上分类成 ans[0]和ans[1] a&(-a)就是计算出这个数,可以参考树状数组. 最后就是注意(nums[i] & a) == 0要加().注意符号运算优先级 class Solution { public: vector<int> singleNumber(vector<int>& nums) {…
Given an array of numbers nums, in which exactly two elements appear only once and all the other elements appear exactly twice. Find the two elements that appear only once. For example: Given nums = [1, 2, 1, 3, 2, 5], return [3, 5]. Note: The order…
Given an array of integers, every element appears twice except for one. Find that single one. class Solution { public: int singleNumber(vector<int>& nums) { int size=nums.size(); ||nums.empty()) ; ; ;i<size;++i) res^=nums[i]; return res; } };…
Problem: Given an array of numbers nums, in which exactly two elements appear only once and all the other elements appear exactly twice. Find the two elements that appear only once. For example: Given nums = [1, 2, 1, 3, 2, 5], return [3, 5]. Note: T…
Given an array of numbers nums, in which exactly two elements appear only once and all the other elements appear exactly twice. Find the two elements that appear only once. For example: Given nums = [1, 2, 1, 3, 2, 5], return [3, 5]. 代码如下: public cla…
136. Single Number 意思就是给你一堆数,每个数都出现了两次,只有一个数只出现了一次,找出这个数 位运算(和c艹一样) &:按位与 |:按位或 ^:异或(一样为0,不一样为1) 再说一下异或的性质,满足交换律和结合律 因此: 对于任意一个数n n ^ 0 = n n ^ n = 0 对于这道题来说,所有数依次异或剩下的就是那个数了 class Solution(object): def singleNumber(self, nums): ans = 0 for i in nums…
136. Single Number Given an array of integers, every element appears twice except for one. Find that single one. (Easy) Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 分析: 第一问属于技巧题,做过就会,…
题目 Given an array of numbers nums, in which exactly two elements appear only once and all the other elements appear exactly twice. Find the two elements that appear only once. For example: Given nums = [1, 2, 1, 3, 2, 5], return [3, 5]. Note: The ord…
[本文链接] http://www.cnblogs.com/hellogiser/p/single-number-of-array-with-other-three-times.html [题目] int类型数组中除了一个数出现一次或两次以外,其他数都出现三次,求这个数. [分析]  C++ Code  123456789101112   int singleNumber(int *a, int n) {     ;     ; i < n; i++)     {         ones = …
Single Number III Given 2*n + 2 numbers, every numbers occurs twice except two, find them. Example Given [1,2,2,3,4,4,5,3] return 1 and 5 Challenge O(n) time, O(1) extra space. 可耻的百度了..点这里 还是好理解的.当然不一定要用最低位的1,任意找一个1即可.不过有lowbit = xor & -xor 这个公式当然是这个…
Given an array of numbers nums, in which exactly two elements appear only once and all the other elements appear exactly twice. Find the two elements that appear only once. For example: Given nums = [1, 2, 1, 3, 2, 5], return [3, 5]. Note: The order…
题目描述: 给定一个数组,里面只有两个数组,只是出现一次,其余的数字都是出现两次,找出这个两个数字,数组形式输出 原文描述: Given an array of numbers nums, in which exactly two elements appear only once and all the other elements appear exactly twice. Find the two elements that appear only once. For example: G…
给定两个大小为 m 和 n 的有序数组 nums1 和 nums2. 请你找出这两个有序数组的中位数,并且要求算法的时间复杂度为 O(log(m + n)). 你可以假设 nums1 和 nums2 不会同时为空. 示例 1: nums1 = [1, 3] nums2 = [2] 则中位数是 2.0 示例 2: nums1 = [1, 2] nums2 = [3, 4] 则中位数是 (2 + 3)/2 = 2.5分析,这个在C#中,可以先合并数组.然后对数组进行sort,然后分析找出中位数.代码…
题目:找出这两个有序数组的中位数 给定两个大小为 m 和 n 的有序数组 nums1 和 nums2. 请你找出这两个有序数组的中位数,并且要求算法的时间复杂度为 O(log(m + n)). 你可以假设 nums1 和 nums2 不会同时为空. 示例 1: nums1 = [1, 3] nums2 = [2] 则中位数是 2.0 示例 2: nums1 = [1, 2] nums2 = [3, 4] 则中位数是 (2 + 3)/2 = 2.5 方法一:清奇思路,空间换时间(本人写的) cla…