Periodic Strings  A character string is said to have period k if it can be formed by concatenating one or more repetitions of another string of length k. For example, the string "abcabcabcabc" has period 3, since it is formed by 4 repetitions o…

UVa OJ 455 Periodic Strings A character string is said to have period k if it can be formed by concatenating one or more repetitions of another string of length k. For example, the string "abcabcabcabc" has period 3, since it is formed by 4 repe…

Periodic Strings 模板 题意分析 判断字符串的最小周期 代码总览 /* Title:UVA.455 Author:pengwill Date:2016-12-16 */ #include <iostream> #include <cstdio> #include <cstring> using namespace std; char str[100]; int main() { int n; scanf("%d",&n); w…

题意:给出一个字符串,找出它的最小的周期,枚举从1到len的周期,看是否满足. #include<iostream> #include<cstdio> #include<cstring> #include<algorithm> using namespace std; ]; int main() { int ncase,t,i,k,j,len; scanf("%d",&ncase); while(ncase--) { scanf(…

1.题目大意 求一个长度不超过80的字符串的最小周期. 2.思路 非常简单,基本就是根据周期的定义做出来的,几乎不需要过脑. 3.应该注意的地方 (1) 最后输出的方式要注意,不然很容易就PE了.不过个人认为,其实这题Sample Output给的不好 (2) 注意输出的要求是最小周期 4.代码 #include"stdio.h" #include"string.h" #define maxn 80 int main() { int T,m,i,j,flag; ch…

[链接] 我是链接,点我呀:) [题意] 在这里输入题意 [题解] 枚举 [代码] #include <bits/stdc++.h> using namespace std; const int N = 100; char s[N]; int len; bool check(int L) { if (len%L != 0) return false; for (int i = L; i < len; i++) if (s[i] != s[i%L]) return false; retur…

​ A character string is said to have period k if it can be formed by concatenating one or more repetitions of another string of length k. For example, the string "abcabcabcabc" has period 3, since it is formed by 4 repetitions of the string &quo…

http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=1620 ProblemG ILove Strings!!! Input:Standard Input Output:Standard Output TimeLimit: 4 Seconds Hmmmmmm----strings again :) Then it must be an easy…

Given two strings s and t, determine if they are isomorphic. Two strings are isomorphic if the characters in s can be replaced to get t. All occurrences of a character must be replaced with another character while preserving the order of characters.…

Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 给出两个字符串,返回对应数字想乘后的字符串,由于这个字符串可能很大,所以不能采用一般的乘法,这里用的方法是模拟手工的乘法运算,算法 本身很简单,就是当时写的时候有些很小的细节搞错了,找了…