题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5113 题目大意:给你N*M的棋盘,K种颜色,每种颜色有c[i]个(sigma(c[i]) = N*M),现在给棋盘染色,使得相邻的两个棋盘染成不同的颜色,并且把所有颜色用完. 因为棋盘最大为5*5的,因此可以考虑搜索+剪枝. 从左到右,从上到下看当前格子能够染成什么颜色. 有一个限制性条件,就是说如果当前棋盘的格子数量的一半小于一种颜色的数量时,那么就一定有两个相邻的棋盘被染成了相同的颜色. 因为假…

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5113 Black And White Time Limit: 2000/2000 MS (Java/Others)Memory Limit: 512000/512000 K (Java/Others) 问题描述 In mathematics, the four color theorem, or the four color map theorem, states that, given any…

Black And White Time Limit: 2000/2000 MS (Java/Others) Memory Limit: 512000/512000 K (Java/Others) Total Submission(s): 929 Accepted Submission(s): 238 Special Judge Problem Description In mathematics, the four color theorem, or the four color map th…

Counting Cliques Time Limit: 8000/4000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 539    Accepted Submission(s): 204 Problem Description A clique is a complete graph, in which there is an edge between every pair…

Black And White Time Limit: 2000/2000 MS (Java/Others)    Memory Limit: 512000/512000 K (Java/Others)Total Submission(s): 3937    Accepted Submission(s): 1082Special Judge Problem Description In mathematics, the four color theorem, or the four color…

题目链接:http://acm.split.hdu.edu.cn/showproblem.php?pid=5887 题解:这题一看像是背包但是显然背包容量太大了所以可以考虑用dfs+剪枝,贪心得到的不一定是正确答案.当然这题还可以用背包来写,其实这就用到了dp的一些优化就是存状态,递推过程中有些状态是多余的没必要计算这样就可以大大减少空间的利用和时间的浪费 第一份是dfs+剪枝的写法第二份是背包+map存状态的写法. #include <iostream> #include <cstri…

Description In mathematics, the four color theorem, or the four color map theorem, states that, given any separation of a plane into contiguous regions, producing a figure called a map, no more than four colors are required to color the regions of th…

题目链接 题意 : 给出 n * m 的网格.要你用 k 种不同的颜色填给出的网格.使得相邻的格子颜色不同.若有解要输出具体的方案 分析 : 看似构造.实则搜索.手构构半天没有什么好想法 直接搜就行了.注意加上剪枝 当剩下格子不足以让剩下颜色数量最多的颜色产生间隔的话则返回 具体也很好实现.即 max( 剩下的最多数量的那种颜色的数量 ) > ( 还剩多少格子 + 1 ) / 2 #include<bits/stdc++.h> using namespace std; ; int rem…

http://acm.hdu.edu.cn/showproblem.php?pid=5113 题意:给你n*m的格子,然后在每个格子内涂色,相邻格子不能同色,然后给你每个颜色涂的格子的固定个数,然后可不可以实现,可以实现输出任意一种,否则输出NO 思路:dfs枚举,剪纸,每种颜色剩余的个数不能超过剩余格子数的一半,如果剩余格子数是奇数,不能超过一半加1,偶数是一半. #include <cstdio> #include <cstring> #include <algorith…

Problem Description Like everyone, cows enjoy variety. Their current fancy is new shapes for pastures. The old rectangular shapes are out of favor; new geometries are the favorite.I. M. Hei, the lead cow pasture architect, is in charge of creating a…