Oil Deposits Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 8274 Accepted Submission(s): 4860 Problem Description The GeoSurvComp geologic survey company is responsible for detecting underground…

题目:   The GeoSurvComp geologic survey company is responsible for detecting underground oil deposits. GeoSurvComp works with one large rectangular region of land at a time, and creates a grid that divides the land into numerous square plots. It then a…

HDOJ(HDU).1241 Oil Deposits(DFS) [从零开始DFS(5)] 点我挑战题目 从零开始DFS HDOJ.1342 Lotto [从零开始DFS(0)] - DFS思想与框架/双重DFS HDOJ.1010 Tempter of the Bone [从零开始DFS(1)] -DFS四向搜索/奇偶剪枝 HDOJ(HDU).1015 Safecracker [从零开始DFS(2)] -DFS四向搜索变种 HDOJ(HDU).1016 Prime Ring Problem (…

HDU 1241  Oil Deposits L -DFS Time Limit:1000MS     Memory Limit:10000KB     64bit IO Format:%I64d & %I64u   Description The GeoSurvComp geologic survey company is responsible for detecting underground oil deposits. GeoSurvComp works with one large r…

HDU 1241 题目大意:给定一块油田,求其连通块的数目.上下左右斜对角相邻的@属于同一个连通块. 解题思路:对每一个@进行dfs遍历并标记访问状态,一次dfs可以访问一个连通块,最后统计数量. /* HDU 1241 Oil Deposits --- 入门DFS */ #include <cstdio> int m, n; //n行m列 ][]; /* 将和i,j同处于一个连通块的字符标记出来 */ void dfs(int i, int j){ || j < || i >=…

HDU 1241 Oil Deposits(石油储藏) 00 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)   Problem Description - 题目描述 The GeoSurvComp geologic survey company is responsible for detecting underground oil deposits. GeoSurvComp works with one large…

题目传送门 /* DFS:油田问题,一道经典的DFS求连通块.当初的难题,现在看上去不过如此啊 */ /************************************************ Author :Running_Time Created Time :2015-8-4 10:11:11 File Name :HDOJ_1241.cpp ************************************************/ #include <cstdio> #i…

Oil Deposits Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 16542    Accepted Submission(s): 9500 Problem Description The GeoSurvComp geologic survey company is responsible for detecting underg…

题目链接:Oil Deposits 解析:问有多少个"@"块.当中每一个块内的各个"@"至少通过八个方向之中的一个相邻. 直接从"@"的地方開始向相邻八个方向搜索,每搜到一个格子.就将它替换成".",一次搜索就会搜索完一个块,记录搜索的次数为答案. AC代码: #include <cstdio> #include <cstring> #include <queue> using namesp…

解题思路:第一道DFS的题目--- 参看了紫书和网上的题解-- 在找到一块油田@的时候,往它的八个方向找,直到在能找到的范围内没有油田结束这次搜索 可以模拟一次DFS,比如说样例 在i=0,j=1时,发现第一块油田,对它DFS,这样经过一次DFS,所有的油田都被找出来了,被记0 Oil Deposits Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submiss…