有表格存放每个顾客拥有的票.现在想查看哪些顾客的票不是连号,即有间隔.并找出间隔的开始与结束数字. create table tickets ( buyer_name char(5) not null, ticket_nbr int default 1 not null check (ticket_nbr>0), primary key (buyer_name,ticket_nbr) ) insert into tickets values('one',2),('one',3),('one',4…