An easy problem Time Limit: 8000/5000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 467    Accepted Submission(s): 258 Problem Description One day, a useless calculator was being built by Kuros. Let's assume that…
Problem Description In this problem you need to make a multiply table of N * N ,just like the sample out. The element in the ith row and jth column should be the product(乘积) of i and j. Input The first line of input is an integer C which indicate the…
http://poj.org/problem?id=2826 An Easy Problem?! Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 10505   Accepted: 1584 Description It's raining outside. Farmer Johnson's bull Ben wants some rain to water his flowers. Ben nails two woode…
An easy problem A Time Limit: 2000/1000MS (Java/Others)     Memory Limit: 65535/65535KB (Java/Others) Submit Status N个数排成一列,Q个询问,每次询问一段区间内的数的极差是多少. Input 第一行两个整数N(1≤N≤50000),Q(1≤Q≤200000).接下来一行N个整数a1 a2 a3 ....an,(1≤ai≤1000000000).接下来Q行,每行两个整数L,R(1≤L…
An easy problem Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5475 Description One day, a useless calculator was being built by Kuros. Let's assume that number X is showed on the screen of calculator. At first,…
Problem Description We once did a lot of recursional problem . I think some of them is easy for you and some if hard for you. Now there is a very easy problem . I think you can AC it. We can define sum(n) as follow: if i can be divided exactly by 3 s…
D. Ability To Convert time limit per test 1 second Cmemory limit per test 256 megabytes input standard input output standard output Alexander is learning how to convert numbers from the decimal system to any other, however, he doesn't know English le…
CJOJ 2485 UVa 11991 生日礼物 / UVa 11991 Easy Problem from Rujia Liu? Description (原题来自刘汝佳<训练指南>Page187,UVa 11991.) 可爱的小F就要过生日啦,为了刷存在感,我们的小F十分诚恳(xian de mei shi)地向女神小E要生日礼物.不过傲娇(2333)的小E当然不会随便答应的啦~为了为难小F,小E就说: "如果你能做出这道简单题,我就给你礼物:如果做不出来,嘿嘿嘿嘿-"…
题目意思: http://acm.hdu.edu.cn/showproblem.php? pid=2601 给出一个数N,求N=i*j+i+j一共同拥有多少种方案. 题目分析: 此题直接暴力模拟就可以.仅仅是须要将上式转化为n+1=(i+1)*(j+1)进行计算就可以. AC代码: /** *hdu2601 An easy problem *意思:求n=i*j+i+j的种类 *分析:转化为n+1=(i+1)*(j+1),求解即可了 */ #include<iostream> #include&…
An Easy Problem Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 8371   Accepted: 5009 Description As we known, data stored in the computers is in binary form. The problem we discuss now is about the positive integers and its binary form.…