题目简述: Given a linked list, remove the nth node from the end of list and return its head. For example, Given linked list: 1->2->3->4->5, and n = 2. After removing the second node from the end, the linked list becomes 1->2->3->5. Note:…
Given a linked list, remove the nth node from the end of list and return its head. For example, Given linked list: 1->2->3->4->5, and n = 2. After removing the second node from the end, the linked list becomes 1->2->3->5. 思路: 最基本的思路肯定…
这道题是LeetCode里的第19道题. 题目要求: 给定一个链表,删除链表的倒数第 n 个节点,并且返回链表的头结点. 示例: 给定一个链表: 1->2->3->4->5, 和 n = 2. 当删除了倒数第二个节点后,链表变为 1->2->3->5. 说明: 给定的 n 保证是有效的. 进阶: 你能尝试使用一趟扫描实现吗? 先求链表长度的暴力法我就不讲了. 关于一趟实现的办法就是先让 back 先走 n 次,此时 front 和 back 产生了长度为 n 的间…
Given a linked list, remove the nth node from the end of list and return its head. For example, Given linked list: 1->2->3->4->5, and n = 2. After removing the second node from the end, the linked list becomes 1->2->3->5. Note:Given n…
思路1:设置两个指针p1,p2指向表头,p1先走n步.再两个指针同时走.当p1指针指到链表尾部时,P2指针已经在需要删除节点的前一位.一定要注意一些细节. class ListNode { int val; ListNode next; ListNode(int x) { val = x; } } public ListNode removeNthFromEnd(ListNode head, int n) { if(head==null||n<=0){ return head; } ListNo…
题目描述:Remove Nth Node From End of List Given a linked list, remove the nth node from the end of list and return its head. For example, Given linked list: 1->2->3->4->5, and n = 2. After removing the second node from the end, the linked list bec…
Given a linked list, remove the nth node from the end of list and return its head. For example, Given linked list: 1->2->3->4->5, and n = 2. After removing the second node from the end, the linked list becomes 1->2->3->5. Note: Given…
Given a linked list, remove the n-th node from the end of list and return its head. Example:                     Given linked list: 1->2->3->4->5, and n = 2.                     After removing the second node from the end, the linked list beco…
题目:Given a linked list, remove the nth node from the end of list and return its head. For example: Given linked list: 1->2->3->4->5, and n = 2. After removing the second node from the end, the linked list becomes 1->2->3->5. struct Li…
Given a linked list, remove the nth node from the end of list and return its head. For example, Given linked list: 1->2->3->4->5, and n = 2. After removing the second node from the end, the linked list becomes 1->2->3->5. Note:Given n…