SQL查询一个表中类别字段中Max()最大值对应的记录 SELECT A.id, A.name, A.version FROM DOC A, (SELECT id, MAX(version) AS version FROM DOC GROUP BY id) AS B WHERE A.id = B.id AND A.version = B.version
(1)oracle使用keep分析函数取最值记录 -- 取工资sal最大的雇员姓名及其工资,以及工资sal最少的雇员姓名及其工资 select deptno, empno, ename, sal, max(ename) keep(dense_rank FIRST order by sal) over (partition by deptno) as min_sal_man, max(sal) keep(dense_rank FIRST order by sal) over (partition
LINQ: var temp = from p in db.jj_Credentials group p by p.ProfessionID into g select new { g.Key, MaxPrice = g.Max(p => p.CredentialsRankID) }; EF: var temp1 = db.jj_Credentials.GroupBy(m => m.ProfessionID).Select(m => m.Max(o => o.Credentials
oracle 中随机取一条记录的两种方法 V_COUNT INT:=0; V_NUM INT :=0; 1:TBL_MYTABLE 表中要有一个值连续且唯一的列FID BEGIN SELECT COUNT(*) INTO V_COUNT FROM TBL_MYTABLE; SELECT TRUNC(DBMS_RADOM.VALUE(1,V_COUNT+1)) INTO V_NUM FROM DUAL; SELECT * FROM TBL_MYTABLE T WHERE T.FID=V_NUM;
sqlserver2005前: --分组取最大最小常用sql--测试环境if OBJECT_ID('tb') is not null drop table tb;gocreate table tb( col1 int, col2 int, Fcount int)insert into tbselect 11,20,1 union allselect 11,22,1 union allselect 11,23,2 union allselect 11,24,5 union allselect 12
在日常编程中,经常遇到要在一组复杂类的集合(Collection)中做比较.取最大值或最小值. 举个最简单的例子,我们要在一个如下结构的集合中选取包含最大值的元素: public class Class<T> where T : struct { public T? Value { get; set; } } var ints = new List<Class<int>>() { }, }, }, }, }; 如果不使用.Net高级特性的做法通常是: var max =
http://blog.csdn.net/acmain_chm/article/details/4126306 http://bbs.csdn.net/topics/390958705 1 我只用到了其中的特殊形式,就是 分组取最新的一条记录: select * from (select * from Table1 order by Score desc) t group by ClsNo 利用的是 group by 只取第一条记录.需要用子查询先把需要的记录排序到第一位 2018/8/21 排
要求:获得按table1_id分组,并且age最大的记录信息,即2.3.5条 方法一: select * from (select * from table2 order by age desc) as a group by a.table1_id 方法二: select a.* from table2 as a where age = (select max(age) from table2 where a.table1_id=table1_id) 方法三: select
数据库原始数据如下:数据库名:tbl_clothers 需求是:按照type分组,并获取个分组中price中的最大值,解决sql如下: 方法一: select * from (select type, name, price from tbl_clothers order by price desc) as a group by a.type; 方法二: select a.* from tbl_clothers as a where price = (select max(price) fr
SELECT SysUserID, UserID, ROW_NUMBER() OVER(PARTITION BY UserID ORDER BY AddTime DESC) AS nums AND SysUserID IN (SELECT userid FROM jdrcadmin.admin WHERE deptId ,,,,) ) 查询结果如下图:
如下图, 计划实现 :按照 parent_code 分组, 取组中code最大值所在的整条记录,如红色部分.(类似hive中: row_number() over(partition by)) select c.* from ( end) as sort_num,(@key_i:=parent_code) as tmp ,@key_i:='') b order by parent_code,code desc) c ; 个人理解, mysql 运行顺序: from >> where >
