SELECT *FROM ( SELECT ROW_NUMBER() OVER( PARTITION BY CONVERT(CHAR(10), DataTime, 120) ORDER BY DataTime DESC ) AS rid, * FROM Hour_4684807221950341358 ) AS tWHERE rid = 1 --沉降监测1 select * from (SELECT * FROM (SELECT *,ROW_NUMBER() OVER (PARTITION BY
在创建完分区表后,可以向分区表中直接插入数据,而不用去管它这些数据放在哪个物理上的数据表中.接上篇文章,我们在创建好的分区表中插入几条数据 insert Sale ([Name],[SaleTime]) values ('张三','2009-1-1') insert Sale ([Name],[SaleTime]) values ('李四','2009-2-1') insert Sale ([Name],[SaleTime]) values ('王五','2009-3-1') insert Sa
1.查询表中重复数据.select * from peoplewhere peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)2.删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录delete from people where peopleId in (select peopleId
create table test1( id number, name varchar2(20) ); ,'jack'); ,'jack'); ,'peter'); ,'red'); insert into test1 values(5,'green'); insert into test1 values(6,'green'); 一 查询表中重复数据 1. 使用exists select a.* from test1 a where exists ( select name from ( se
24小时内记录(即86400秒) $sql="SELECT video_id,count(id)as n FROM `rec_down` WHERE UNIX_TIMESTAMP(NOW())-UNIX_TIMESTAMP(add_time)<=86400 group by video_id order by n desc ";$sql="select a.id,a.title,b.n from video_info a,(".$sql.")b wh
Ⅰ→通过ViewData传递数据,不过需要新建一个类(用来存) NewClass(里面有表1的字段和表2的字段) public class JoinTab1_2 { public int ID { get; set; } public string Name { get; set; } } 控制器中Action public ActionResult Index() {using (DBEntities db = new DBEntities()) { var query = (from tab
<script type="text/javascript"> var t function cleaData() { t = setTimeout(syc, 3000); } function syc() { document.getElementById("Label1").innerText = ""; cleart(t); } </script>
1.方法一(仅适用单个字段):使用 not in ,比较容易理解,缺点是效率低 如:select A.ID from A where A.ID not in (select ID from B): 2.方法二(适用多个字段匹配):使用 left join...on... , "B.ID isnull" 表示左连接之后在B.ID 字段为 null的记录. 如:select A.ID from A left join B on A.ID=B.ID where B.ID is null :
MySql : 有N张表,N未知,每张表都有一个字段(id),每张表的字段结构不完全一样,如何查询所有表里面所有id的最大值?如下图所示: 对上面三张表进行操作的话,结果应该为:9 SQL语句: select greatest( (select max(id) from table_1), (select max(id) from table_2), (select max(id) from table_3) )