/*查询某张表被哪些存储过程或者视图用到的sql语句*/select distinct object_name(id) from syscomments where id in (select id from sysobjects where type in('V','P')) and text like '%表名%'
有两张表:一张A表he一张B表 left join(左联接) 返回包括左表中的所有记录和右表中联结字段相等的记录 :right join(右联接) 返回包括右表中的所有记录和左表中联结字段相等的记录:inner join(等值连接) 只返回两个表中联结字段相等的行: 表A数据: 表B数据: 1.查询两张表中都有的记录: sql: SELECT a.* FROM a INNER JOIN b ON a.a_id = b.b_id; 2.查询表A中有,表B中没有的数据: sql: SELECT a.
注:本文来源于<oracle查询某张表的外键(最终解决办法)> 一:几个查询表外键的脚本 select b.table_name, b.column_name from user_constraints a inner join user_cons_columns b on a.constraint_name = b.constraint_name where a.r_constraint_name in ( select e.constraint_name from user_constra
表名:student 表结构及数据: +----+--------+---------+------+------------+--------------+---------+ | id | name | english | math | birthday | native_place | chinese | +----+--------+---------+------+------------+--------------+---------+ | 1 | 潘怡茹 |
现在有一张表如下Id Name Age Classify Score1 张一 18 一班 122 张二 17 二班 19 3 张三 19 三班 30 我跟据他们的分数进行排名 再去新建一个列存储排序值 ->sql语句如下 select row_number() over(order by Score asc) as number,Id,Name,Age,Classify,Score from u_College order by Score;->产生的效果如下 number Id Name A
#update 和 select在同一张表的时候会显示冲突 报错信息: [Err] 1093 - You can't specify target table 'tb_a' for update in FROM clause update tb_a set sex='boy' where uid =(select uid from tb_a where name ='cyq') #解决方式:嵌套多一个查询表 update tb_a set sex='boy' where uid =(selec
有时,我们需要对比两张表的数据,找到在其中一张表,不在另一张表中的数据 hql 如下: SELECT * FROM (SELECT id FROM a WHERE dt = '2019-03-17' ) a LEFT JOIN (SELECT id FROM b ) b ON a.id = b.id WHERE b.id IS NULL;
MySql : 有N张表,N未知,每张表都有一个字段(id),每张表的字段结构不完全一样,如何查询所有表里面所有id的最大值?如下图所示: 对上面三张表进行操作的话,结果应该为:9 SQL语句: select greatest( (select max(id) from table_1), (select max(id) from table_2), (select max(id) from table_3) )
项目中遇到一个问题, 有4张表, 然后相互之间有3张关系表关联, 一共七张表. 想要从顶层表查询最底层表的记录,不能写7层嵌套. 用Linq实现特别简单, 表:User,Role,Module,Function以及User_Role,Role_Module, Module_Function, var fs = (from r in DB.user_role from m in DB.role_module from f in DB.module_function where r.User_Re
同一张表存在类似多级菜单的上下级关系的数据,查询出符合条件的某些数据的id拼接成一个字段返回: SELECT CONCAT(a.pid, ',', b.subid) AS studentIDS FROM (SELECT id as pid, sourceCode as scode FROM student WHERE studentType='父级条件1' AND studentCode='父级条件2') a LEFT JOIN (SELECT id as subid, parentCode p
1.查询表中重复数据.select * from peoplewhere peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)2.删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录delete from people where peopleId in (select peopleId
转载:https://blog.csdn.net/qq13650793239/article/details/81142134 mysql数据库中information_schema 数据库存储了数据库很多信息,可以通过查询tables表来获得所需要的表相关信息. mysql> select table_name,table_rows from tables order by table_rows desc limit 10;+--------------------+------------
(user 为要更改数据的表 ,set后边需要更改的内容, where后加条件) update user a,user_copy b set a.manager_introduct=b.rwjs where a.funds_manager_id=b.fund_manager_id and resource='***'
SELECT id AS kid, NAME, IF (t1.kpi, t1.kpi, 0) AS kpi, t1.sort, STATUS, t1.kpi_idFROMform_kpi_nameLEFT JOIN ( SELECT kpi_id AS i, kpi, sort, username, id AS kpi_id FROM faw_form_kpi WHERE username = '123') AS t1 ON form_kpi_name.id = t1.iWHEREform_kp