一.思路:首先判断这个查询的是emp表,需要接收值,声明一个rowtype类型接收数据即可,第二是,存在exception,需要处理,exception中有两种异常,分别处理即可,分别输出即可. 二.在增删改之后加上commit提交事物. 三.具体实现 declare -- 声明rowtype类型接收数据即可 v_emp emp%rowtype; begin -- 查询员工中姓为“SMITH” select * into v_emp from emp where ename='SMITH'; d
--查询并打印员工的姓名和薪水 --set serveroutput on /* 1.光标的属性 %found:假设取到了记录就是true否则是false: %notfound: */ declare --定义一个光标 cursor cemp is select ename,sal from emp; --为光标定义相应的变量 pename emp.ename%type; psal emp.sal%type; begin --打开光标 open cemp; loop --取一条记录 into后面
一.思路:首先输出需要变量接收,需要声明变量,于是考虑什么变量类型比较合适,在这我用的是table类型,最后,查询出来,循环输出即可. 二.具体实现 -- 编写一个PL/SQL块,输出所有员工的员工姓名.员工号.工资和部门号 declare -- 声明table类型的对象,属性 员工姓名:ename,员工号:empno,工资:sal ,部门:deptno type emp_table_type is table of emp%rowtype index by binary_integer; --
题目描述 查找排除当前最大.最小salary之后的员工的平均工资avg_salary.CREATE TABLE `salaries` ( `emp_no` int(11) NOT NULL,`salary` int(11) NOT NULL,`from_date` date NOT NULL,`to_date` date NOT NULL,PRIMARY KEY (`emp_no`,`from_date`));输出格式: avg_salary 69462.5555555556 SQL: sele
先查询再插入,改为存储过程 create or replace procedure PRO_REVENUE_SI(l_p_cd in Varchar2, l_c_cd in Varchar2, l_prod_type in Varchar2, l_identity_type in Varchar2, l_industry_type_id in Varchar2, l_p_id in Varchar2, l_c_id in Varchar2, l_region_name in Varchar2,
创建表:Create table If Not Exists Employee (Id int, Name varchar(255), Salary int, DepartmentId int);Create table If Not Exists Department (Id int, Name varchar(255));Truncate table Employee;insert into Employee (Id, Name, Salary,DepartmentId) values ('
Train Problem I 时间限制:3000 ms | 内存限制:65535 KB 难度:2 描述 As the new term comes, the Ignatius Train Station is very busy nowadays. A lot of student want to get back to school by train(because the trains in the Ignatius Train Station is the fastest all o
